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Yakvenalex [24]
3 years ago
12

In circle N with m \angle MNP= 48m∠MNP=48 and MN=16MN=16 units find area of sector MNP. Round to the nearest hundredth.

Mathematics
2 answers:
Lisa [10]3 years ago
8 0

Answer:

10.4

Step-by-step explanation:

Area of sector=central angle/360(area)

=46/360(π5^2)

=10.04

Dafna11 [192]3 years ago
4 0

Answer:

A=107 square\ unit

Step-by-step explanation:

From the question we are told that:

 \angle MNP= 48m

 \angle  MN=16 unit

Generally the equation for Area of a sector A is mathematically given by

 A=\frac{\theta}{360}*\pi*r^2

 A=\frac{48}{360}*3.14*16^2

 A=107.18 square\ unit

 A=107 square\ unit

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3 years ago
Can someone tell me… Given the right triangle ABC, what is the value of tan(A)?
sergey [27]

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C

Step-by-step explanation:

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6 0
3 years ago
Is 3/7 and 7/3 the same on the number length in the fraction line?
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3 0
3 years ago
On the average, a grocer sells three of a certain article per week. How many of these should he have in stock so that the chance
olga2289 [7]

Answer:

7

Step-by-step explanation:

This is a Poisson distribution problem with the formula;

P(x;μ) = (e^(-μ)) × (μ^(x))/x!

We are told that the grocer sells three of a certain article per week. Thus;

μ = 3

Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.

This means;

P(X > k) < 0.01

This can be rewritten as;

P(X ≤ k) < 0.99

Let's try x = 8

P(8;3) = (e^(-3)) × (3^(8))/8!

P(8;3) = 0.008

But; P(X ≤ 8) = 1 - 0.008 = 0.992

This is more than 0.99 and thus is not the answer

Let's try x = 7

P(7;3) = (e^(-3)) × (3^(7))/7!

P(7;3) = 0.022

But; P(X ≤ 7) = 1 - 0.022 = 0.978

Thus is less than 0.99.

Thus, stock should be 7

5 0
2 years ago
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