The area of a parallelogram is given by
Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.
If instead we choose the 11 inches side as the base, the height is h.
So, we can express the area in this two equivalent ways:
Solving for h, we have
do: first of first bracket x first of 2nd bracket
+( first of 1st bracket x 2nd of 2nd bracket)
+(2nd of 1st bracket x 1st of 2nd bracket)
+ (2nd of 1st bracket x 2nd of 2nd bracket)
== 10n -16n +20n+32= 14n+32
8a - 4 = 25 + 6 (a - 8)
(distribute the 6)
8a - 4 = 25 + 6a - 48
(combine like terms 25 - 48)
8a - 4 = 6a - 23
( subtract 6a from both sides)
2a - 4 = -23
(add 4 to both sides)
2a = -19
(divide both sides by 2)
a = - 9.5
////CHECK/////
8 (-9.5) - 4 = 25 + 6 ( -9.5 -8)
(plug each side into a calculator)
-80 = -80
FINAL ANSWER:
a = -9.5
3:5
3+5=8
82÷8=10.25
3(10.25):5(10.25)
30.75:51.25
the answer is 30.75:51.25
Let A = 0.0009, it is equivalent to A = 9^-4 = (9^-2)^2
so sqrt A =sqrt (9^-2)^2 = (9^-2)
<span>he real square roots of 0.0009 is 0.09</span>
