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3 years ago

Seven less than eight times a number is -12

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

Answer:

8-7n=-12

Step-by-step explanation:

aliina [53]3 years ago

5 0

Answer:

19/8

Step-by-step explanation:

8x-7=-12

8x=19

x=19/8

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2 years ago

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NikAS [45]

Step-by-step explanation:

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3 years ago

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mart [117]

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3 years ago

Hight =

Mandarinka [93]

Answer:

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Step-by-step explanation:

I hope that is useful for you

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2 years ago

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 <u>more</u> Small boxes sold than Large boxes.

Step-by-step explanation:

<u>This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable. </u>

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have<u> two equations</u> of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

<u>Given Information:</u>

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were<u> 10 Large Boxes and 20 Small Boxes sold</u>, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

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3 years ago