<span>3.75 gallons need to be drained and replaced with bleach.
Change the problem to "What amounts of a 100% solution and a 4% solution is needed to make 90 gallons of a 8% solution?" Given that, we'll use the following values.
x = amount of 4% solution.
90-x = amount of a 100% solution.
The equation to solve then becomes.
0.04 x + (90-x) = 0.08 * 90
0.04 x + 90 - x = 7.2
Add x to both sides
0.04x + 90 = 7.2 + x
Subtract 0.04x from both sides
90 = 7.2 + 0.96x
Subtract 7.2 from both sides
82.8 = 0.96x
Divide both sides by 0.96
86.25 = x
So you now know that you need 86.25 gallons of the original 4% solution and (90-86.25) = 3.75 gallons of the bleach to make the desired 90 gallons.
So simply drain 3.75 gallons from the tank and replace with bleach.</span>
Answer:
<h2>Physics</h2>
Explanation:
This definition was given by Isaac Newton.
He defined three "Laws of Motion" that describe what happens when forces act on objects
Answer:
Rutherford predicted that an atom has a dense core called a <u>nucleus</u>.
Explanation:
Ernest Rutherford was a physicist who is known as the father of nuclear physics. He suggested an atomic model known as the Rutherford model. According to him, the atom consists of a tiny, dense, positively charged core called a nucleus and negatively charged particles called electrons that circulate around it The nucleus consists of positively charged particles called protons and neutral particles called neutrons.
Answer:
The value
Explanation:
From the question we are told that
The thickness of the air is
The temperature is
The total pressure is
The partial pressure of Ammonia first side is
The partial pressure of Ammonia to the second side is
Rate of flow of ammonia is
Generally the molar flux of ammonia is mathematically represented as
Here R is the gas constant with value
=>
Answer: 7.07 grams
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.052 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.052 moles of give = of
Mass of
Thus 7.07 g of will be produced from the given masses of both reactants.