Ask question

Ask question

All categories

3 years ago

9

What factors affect water quality?In a typical drinking-water treatment process, ____________________ is when air is forced thro

ugh the water to reduce unpleasant odors and taste.

1 answer:

ki77a [65]3 years ago

3 0

Aeration is the answer to your question

You might be interested in

Taya2010 [7]

Answer:

The correct answer is B) electronegativities of the bonded atoms in a molecule of the compound .

Explanation:

When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated

In simple words a bond will be polar when the bonding electrons are not equally shared by two atoms.As a result the atom attract the bonding electron pair towards itself gain partial negative charge and the other atom gains partial positive charge.

For HCl is a polar compound because H and Cl atom differ in their electronegativities,as a result the bonding electron pair is not shared equally by H and Cl atoms.

8 0

3 years ago

Chemistry, please help! Thanks.

Ilya [14]

Answer:

d. The gold(III) ion is most easily reduced.

Explanation:

The standard reduction potentials are

Au³⁺ + 3e⁻ ⟶ Au; 1.50 V

Hg²⁺ + 2e⁻ ⟶ Hg; 0.85 V

Zn²⁺ + 2e⁻ ⟶ Zn; -0.76 V

Na⁺ + e⁻ ⟶ Na; -2.71 V

A <em>more positive voltage</em> means that there is a <em>stronger driving force</em> for the reaction.

Thus, Au³⁺ is the best acceptor of electrons.

Reduction Is Gain of electrons and, Au³⁺ is gaining electrons, so

Au³⁺ is most easily reduced.

4 0

3 years ago

Why was the term inert gases dropped? Why was the term inert gases dropped? The term "inert" was dropped because hydrogen was ad

xxMikexx [17]

Answer:

B) The term "inert" was dropped because it no longer described all the group 8A elements.

Explanation:

Inert elements in chemistry simply refers to elements that are chemically inactive and are not expected to form any compounds. this is the general belief for the group 8 elements as they all have complete duplet/octet configurations (and ideally, they ought to be very stable with no tendency to form compounds by participating in the loss and gain of electrons). However the discovery of compounds like xenon tetrafluoride (XeF4) proved this to be wrong.

Again, the reason the term - inert gses was droppedis beacause this term is not strictly accurate because several of them do take part in chemical reactions.

After dropping the term - Inert gases, they are now referred to as noble gases.

8 0

4 years ago

The Thermite reaction reacts iron (III) oxide, Fe2O3 with aluminium powder, Al, to form aluminium oxide, Al2O3 and iron, Fe. Fe2

Rama09 [41]

So, I don't know the answer for b but I think I found the answer for a.

I sincerely hope this isn't wrong

3 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

3 years ago