<span>The combined Boyle's and Charles' gas law says P1V1/T1 = P2V2/T2 </span>
<span>In this case we have (2.5 atm) (900 ml) / 298 K = (P2) (450 ml) / 336 K -----> </span>
<span>7.55 = 1.34P2 -----> P2 = 7.55 / 1.34 = 5.63 atm</span>
Answer:
The pressure inside the container is 34.97 atm
Explanation:
Given:
V=50L R= 0.0821LatmK^-1mol^-1
n= 45mol T= 473k
PV=nRT
P= nRT/V
= 45mol*0.0821Latmmol^-1K^-1*473K/ 50L
=34.95atm
Answer:
a. Rate = k×[A]
b. k = 0.213s⁻¹
Explanation:
a. When you are studying the kinetics of a reaction such as:
A + B → Products.
General rate law must be like:
Rate = k×[A]ᵃ[B]ᵇ
You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.
If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1
Rate = k×[A]¹[B]ᵇ
In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]
Rate = k×[A][B]⁰
<h3>Rate = k×[A]</h3>
b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:
Rate = k×[A]
0.320M/s = k×[1.50M]
<h3>k = 0.213s⁻¹</h3>
Chemical energy is stored within atoms