All categories

3 years ago

Rewrite y=a(1/3)^3t in the form y = a(1+r)^t or y = a(1 –r)^t

Mathematics

1 answer:

pshichka [43]3 years ago

6 0

Answer:

sorry

Step-by-step explanation:

sorry I cannot help u because I have not seen this type of question before and I have not learn I am in 7 classes

You might be interested in

Five observations taken for two variables follow.

I am Lyosha [343]

Answer:

a) Figure attached

b) If we see the scatter plot we can conclude that the possible relation between x and y is linear and with a positive correlation since when the values of x increases the values for y increases as well.

c) $Cov (X,Y) = \frac{\sum_{i=1}^n (x_i -\bar X)(y_i -\bar Y)}{n-1}$

We can find the numerator like this:

$\sum_{i=1}^5 (6-16)(6-10)+(11-16)(9-10)+(15-16)(6-10)+(21-16)(17-10)+(27-16)(12-10)=106$

And then:

$Cov(X,Y) = \frac{106}{5-1}=26.5$

d) $r=\frac{5(906)-(80)(50)}{\sqrt{[5(1552) -(80)^2][5(586) -(50)^2]}}=0.693$

Step-by-step explanation:

Part a

For this part we use excel in order to create the scatterplot and we got the result on the figure attached.

Part b

If we see the scatter plot we can conclude that the possible relation between x and y is linear and with a positive correlation since when the values of x increases the values for y increases as well.

Part c

The sample covariance is defined as:

$Cov (X,Y) = \frac{\sum_{i=1}^n (x_i -\bar X)(y_i -\bar Y)}{n-1}$

We can find the numerator like this:

$\sum_{i=1}^5 (6-16)(6-10)+(11-16)(9-10)+(15-16)(6-10)+(21-16)(17-10)+(27-16)(12-10)=106$

And then:

$Cov(X,Y) = \frac{106}{5-1}=26.5$

Part d

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=5 $\sum x = 80, \sum y = 50, \sum xy = 906, \sum x^2 =1552, \sum y^2 =586$

$r=\frac{5(906)-(80)(50)}{\sqrt{[5(1552) -(80)^2][5(586) -(50)^2]}}=0.693$

So then the correlation coefficient would be r =0.693

3 0

3 years ago

Find the length of mAB using the figure below<br> (please see photo)

Mrrafil [7]

Answer:

Explanation:

Look at the number line and count the number of increments needed to get from point A to B.

4 0

2 years ago

Read 2 more answers

1,352 pounds is what fraction short of a ton?

Aleksandr [31]

$A \ short \ ton \ is \ 2 \ 000 pounds \\ \\\frac{1 \ 352}{2 \ 000} = \frac{169}{250} \ \ \ | divided \ numerator \ and \ denominator \ by \ 8 \\ \\ \\ Answer : \ A) \ \ \frac{ 169}{250 }$

4 0

4 years ago

Read 2 more answers

I have trouble understanding word problems. May I please have help with number 15? Thank you very much!

guapka [62]

Basically you do fractions side by side. so, 6/3=15/h and then cross multiply to get your answer so that would give you 3h=80, then divide 80÷3

5 0

3 years ago

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample

dem82 [27]

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. If a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. The margin of error of the sample mean is 83.71%.

7 0

4 years ago