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Korvikt [17]
3 years ago
5

Ill give brainliest just please hurry :)

Mathematics
1 answer:
Pie3 years ago
7 0
Y=1:5x is the forest answer i hope this helps
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What is 23 fl oz = ______ c
astraxan [27]

Answer:

2.875c

Step-by-step explanation:

3 0
3 years ago
A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
sveta [45]

Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

7 0
3 years ago
the graph shows the distance a car travels over a certain amount of time. what is the ratio of kilometers traveled to the time i
Mumz [18]
A. 40 km/h
this because (2,80)/2 is (1,40) or 40/1, so it would be 40 km/h
8 0
3 years ago
Find the sum (a-b)(2a+4b)
Mama L [17]
(a-b)(2a+4b) = 2a² - 2ab + 4ab - 4b² =  2a² + 2ab - 4b²
7 0
3 years ago
Solve for the value of x by applying the definitions of complementary and supplementary angles
Tatiana [17]

9514 1404 393

Answer:

  x = 52

Step-by-step explanation:

The square corner symbol indicates the sum of the marked angles is 90°. (They are complementary.)

  (x +3)° +35° = 90°

  x° = 90° -38° = 52°

  x = 52

4 0
3 years ago
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