Ill give brainliest just please hurry :)

Refer to the figure to answer the question.

tresset_1 [31]

Answer:

It's HG

Step-by-step explanation:

The line of intersection is where they cross, and this line is the line HG

7 0

3 years ago

I need help please?!!

Rasek [7]

Hope this helps have a nice day:)

3 0

3 years ago

Solve the following proportion: (round to the nearest tenths place if necessary)

romanna [79]

Solution:

4/7 = 10/x

To find the solution to the proportion, we will need to simplify the equation (4/7 = 10/x)

4/7 = 10/x
=> 4x = 70
=> x = 70/4 = 35/2 = 17.5.

Hoped this helped!

8 0

2 years ago

Read 2 more answers

A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon

melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.

X~ Uniform(0,100)

Then the probability mass function is given as follows.

$f(x) = P(X=x) = 1/100 \,\,\,\, \text{if} \,\,\,\, 0 \leq x \leq 100\\f(x) = P(X=x) = 0 \,\,\,\, \text{otherwise}$

Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located 70 meters away from city A then the mid point between 20 and 70 is (70+20)/2 = 45 then we can represent D as follows

$D(x) =\left\{ \begin{array}{ll} x & \mbox{if } 0\leq x \leq 20 \\ x-20 & \mbox{if } 20\leq x < 45\\ 70-x & \mbox{if } 45 \leq x \leq 70\\ x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.$

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable $Y = D(X)$ , $Y$ is a random variable as well, remember that there is a theorem that says that

$E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx$

Where $f(x)$ is the probability mass function of X. Using the information of our problem

$E[Y] = \int\limits_{-\infty}^{\infty} D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx \bigg]\\= \frac{51}{4} = 12.75$

3 0

3 years ago

The packaging lists a model airplane’s length as 10.5 in. It also gives the scale as 1:83. What is the length of the actual airp

Lana71 [14]

$\bf \cfrac{\stackrel{model}{length}}{\stackrel{actual}{length}}\qquad 1:83\qquad \cfrac{1}{83}\implies \cfrac{1}{83}=\cfrac{10.5}{x}\implies x=\cfrac{83\cdot 10.5}{1}
\\\\\\
x=871.5~inches
\\\\\\
\textit{there are 12 inches in 1 foot, thus }
\\\\\\
871.5~\underline{in}\cdot \cfrac{ft}{12~\underline{in}}\implies 72.625~ft 
\qquad \approx 73~ft$

6 0

3 years ago