Answer:
a)This solution matches with the original equation and its solution
b)This solution matches with the original equation and its solution
c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
Step-by-step explanation:
i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.
therefore 1.5x = 10.5 therefore x = 7
a) let the number be x
therefore if
then the number x = 7.
This solution matches with the original equation and its solution
b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 7.
This solution matches with the original equation and its solution
c)if nine quarters of a number, say x, increased by three halves is fifty one
quarters, the number is x = 5,
![\frac{9}{4} x + \frac{3}{2} = \frac{51}{4} \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B4%7D%20x%20%2B%20%5Cfrac%7B3%7D%7B2%7D%20%20%3D%20%5Cfrac%7B51%7D%7B4%7D%20%20%5CRightarrow%20%209x%20%3D%2051%20-%206%20%3D%2045%20%5Ctherefore%20x%20%3D%205)
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 5.
![2.25x + 1.5 = 12.75 \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5](https://tex.z-dn.net/?f=2.25x%20%2B%201.5%20%20%3D%2012.75%20%20%5CRightarrow%20%209x%20%3D%2051%20-%206%20%3D%2045%20%5Ctherefore%20x%20%3D%205)
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.