100%/x%=148/43
<span>(100/x)*x=(148/43)*x - </span>we multiply both sides of the equation by x
<span>100=3.44186046512*x - </span>we divide both sides of the equation by (3.44186046512) to get x
<span>100/3.44186046512=x </span>
<span>29.0540540541=x </span>
<span>x=29.0540540541
</span>now we have:
<span>43 is 29.0540540541% of 148</span>
Answer:
no i dont think so becuse they can still be angeled in all diffrent directions
Step-by-step explanation:
The answer to your question is: Yes, someone undoubtedly can.
Although you haven't asked to be told or shown how to solve it, I'm here
already, so I may as well stick around and go through it with you.
The sheet is telling you to find the solutions to two equations, AND THEN
DO SOMETHING WITH THE TWO SOLUTIONS. But you've cut off the
instructions in the pictures, so all we have are the two equations, and
you'll have to figure out what to do with their solutions.
<u>First equation:</u>
(2/5) x - 6 = -2
Add 6 to each side:
(2/5) x = 4
Multiply each side by 5:
2x = 20
Divide each side by 2 :
<u>x = 10</u>
<u>Second equation:</u>
-3y + 1/4 = 13/4
Subtract 1/4 from each side:
-3y = 12/4
Multiply each side by 4 :
-12 y = 12
Divide each side by -12 :
<u> y = -1</u>
12, 20, 16, 10, 17, 9, 23, 13
1. add them all up
=120
divide by the number of numbers
120/8
=15
15 is the MAD
Each ream weighs 5 lb . so, reducing 10 lb means removing 2 reams from the 12. so, how do we arrange the 10 reams so that its easy to carry?
i thinks that 3 stacks will not work as it wont be a symmetric arrangement as 1 will be left out. So, 2 stacks of 5 each would be easy to carry. but the stacks should be placed in such a way that the lengths are parallel to each other and not in-line which would increase the length making it comparatively longer. its easier to hold a (2*8.5,11,2*5=17,11,17)compact box.
