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Zielflug [23.3K]
2 years ago
12

Question

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
8 0

Answer:

d=7.8\ g/cm^3

Step-by-step explanation:

Given that,

The dimensions of a rectangular block = 4 cm x 2 cm x 1.5 cm

Mass, m = 93.6 g

We need to find the density of steel. We know that the density of an object is equal to the mass divided by volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{93.6}{4\times 2\times 1.5}\\\\d=7.8\ g/cm^3

So, the density of the steel is 7.8\ g/cm^3.

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Oduvanchick [21]

Answer: yes

Step-by-step explanation:

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2 years ago
he frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status
cluponka [151]

Based on the above, the option that shows the conditional relative frequency table by column is known as option C.

<h3>What is conditional relative frequency table?</h3>

Column conditional relative frequencies is one that is said to  be put together or also computed through the act of dividing each frequency in a frequency table by their other column total to form a column conditional relative frequency table.

Note that Column conditional relative frequencies is one that shows the proportions, or relative frequencies,  through the use of the column totals and as such the option that tells us about this is option c which is:

A graph that has 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0.

See options below

Which shows the conditional relative frequency table by column?

A.  A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0.

B.    A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5.

C.   A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0.

D.   A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0.

Learn more about relative frequency from

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3 0
1 year ago
Please answer 7 and 8, thank you guys for helping! &lt;3
elena-14-01-66 [18.8K]
7: since they went down further you go further from zero: -28-40=-68 or D.
8: they lost 6 and then 8 so 6+8=14 but they lost them so -14 or A :)
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3 years ago
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Answer:

15

Step-by-step explanation:Addentitive property states that any number added with 0 is the original number. so, 15+0=15

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What are the solutions to the equation (x – 2)(x + 5) = 0?
nataly862011 [7]

A product of two (or more) factor can be zero if and only if at least one of the factors is zero.

In other words, you cannot multiply two non-zero real numbers, and have zero as a result.

So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

x-2 = 0 \iff x=2

The second factor is zero if

x+5 = 0 \iff x=-5

4 0
3 years ago
Read 2 more answers
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