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Anna71 [15]
3 years ago
11

If an object floats, the volume of the displaced water is equal to the volume of the portion of the object that's above the surf

ace of the water.
true or false
Physics
2 answers:
diamong [38]3 years ago
4 0

Answer:

FALSE

Explanation:

When object float in water then it means that weight of the object is counterbalanced by the buoyancy force.

Here as we know that buoyancy force is the weight of water displaced by the object.

So here when object is submerged into the water then the submerged part of the volume of object will displace exactly the same volume of water and that volume of water will exert upwards buoyancy force on the object.

So here this statement is not true as it says that volume of water displaced is volume above the surface of water while it must be like volume of water displaced must be equal to volume of submerged part of the object.

Virty [35]3 years ago
4 0

Answer: false

Explanation: the volume of water displaced is not equal to the volume of the object because the object is not submerged by the water. So the water displaced is the down trust force exerted on the water by the object

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I’m confused on this worksheet can someone help
Finger [1]

Answer:

well for C the horse is at rest at 10 to 15

D is 0 to 10

E is 15 to 25

Explanation:

If you search up examples it will help with this worksheet.

If I am work then I appologize

5 0
3 years ago
A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi
Lubov Fominskaja [6]

Answer:

The moment of inertia is I=\frac{M}{12} a^{2}

Explanation:

The moment of inertia is equal:

I=\int\limits^a_b {r^{2} } \, dm

If r is -\frac{a}{2}

and dm=\frac{M}{a} dr

I=\int\limits^a_b {r^{2}\frac{M}{a}  } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}

I=\frac{M}{a} \int\limits^a_b {r^{2}  } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\  I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}

7 0
4 years ago
Two cars, one of mass 1100 kg, and the second of mass 2500 kg, are moving at right angles to each other when they collide and st
Pie

Answer:

v_{f}=17.47 m/s

Explanation:

Let's use the conservation of momentum to solve it.

p_{initial}= p_{final} (1)

  • The total initial momentum will be: m_{1}v_{1i}+m_{2}v_{2i}
  • The total final momentum will be: m_{1}v_{1f}+m_{2}v_{2f}, but as they stick together after the collision, v1f = v2f = vf.

So we can rewrite (1), using the above information:

m_{1}v_{1i}+m_{2}v_{2i}=m_{1}v_{f}+m_{2}v_{f}

m_{1}v_{1i}+m_{2}v_{2i}=v_{f}(m_{1}+m_{2})

v_{f}=\frac{m_{1}v_{1i}+m_{2}v_{2i}}{m_{1}+m_{2}}

v_{f}=\frac{1100\cdot 14+2500\cdot 19}{1100+2500}

Finally, the magnitude of the velocity of the wreckage of the two cars immediately after the collision is:

v_{f}=17.47 m/s

I hope it helps you!

5 0
3 years ago
What is the speed of the fastest baseball pitch ever thrown?
Annette [7]

The fastest pitch ever thrown was 105 MPH. Hope this helps!

4 0
3 years ago
Q2.
zzz [600]

Answer:

800W

Explanation:

Given the following data;

Voltage = 230 V

Model = VSO Ha

Power = 800 W

Power is calculated by the multiplication of voltage and current flowing through an electric circuit.

Mathematically, power is given by the formula;

Power = current * voltage

The S.I unit for power is Watts and it is a measure of the energy consumption of an electronic device.

3 0
3 years ago
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