Answer:
If I am correct, the answer is D. Law of conservation of energy
Explanation:
the potential energy "converts" to kinetic once Luke is in motion.
Answer:
θ = 6.3 *10³ revolutions
Explanation:
Angular acceleration of the drill
We apply the equations of circular motion uniformly accelerated
ωf= ω₀ + α*t Formula (1)
Where:
α : Angular acceleration (rad/s²)
ω₀ : Initial angular speed ( rad/s)
ωf : Final angular speed ( rad
t : time interval (s)
Data
ω₀ = 0
ωf = 350000 rpm = 350000 rev/min
1 rev = 2π rad
1 min= 60 s
ωf = 350000 rev/min =350000*(2π rad/60 s)
ωf = 36651.9 rad/s
t = 2.2 s
We replace data in the formula (2) :
ωf= ω₀ + α*t
36651.9 = 0 + α* (2.2)
α = 36651.9 / (2.2)
α = 17000 rad/s²
Revolutions made by the drill
We apply the equations of circular motion uniformly accelerated
ωf²= ω₀ ²+ 2α*θ Formula (2)
Where:
θ : Angle that the body has rotated in a given time interval (rad)
We replace data in the formula (2):
(ωf)²= ω₀²+ 2α*θ
(36651.9)²= (0)²+ 2( 17000 )*θ
θ = (36651.9)²/ (34000 )
θ = 39510.64 rad = 39510.64 rad* (1 rev/2πrad)
θ = 6288.31 revolutions
θ = 6.3 *10³ revolutions
Explanation:
Below is an attachment containing the solution.
Well most of the particles did pass through and a few were deflected. but i think the answer is A
Answer: a=-2.4525 m/s^2
d=s=190.3 m
Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr
Fr = 25% of weight
W=mg
W=1750*9.81
W=17167.5
Hence
Frictional force is negative as it acts in opposite direction
According to newton second law of motion
F=ma
hence
given
u= 110 km/h
u=110*1000/3600
u=30.55 m/s
to get t we know that final velocity v=0
