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3 years ago

I’m confused on this worksheet can someone help

Physics

1 answer:

Finger [1]3 years ago

5 0

Answer:

well for C the horse is at rest at 10 to 15

D is 0 to 10

E is 15 to 25

Explanation:

If you search up examples it will help with this worksheet.

If I am work then I appologize

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A stone is thrown vertically upwards with an intinal velocity of 20 m/sec . find the maximum height it reaches and the time by i

serious [3.7K]

Answer:

Maximum height is20m and time taken will be 2second

Explanation:

vi=20m/s

vf=0m/s

g=10m/s^2

Using third equation for objects falling freely

2gh=(vf)^2-(vi)^2

Putting values

2(10m/s^2)h=(0m/s)^2-(20m/s)^2

20h=400m

h=20m

Now we have to find the time

Using first equation of motion for objects falling down freely

vf=vi+at

substituting the equation

(vf-vi)/g=t

(0-20)/10=t

t=2second

4 0

3 years ago

What is the significance of the discovery of exoplanets?

polet [3.4K]

For only through exploration of the unknown we have come as far as we are now.

Discoveries are what laid the foundation for the technology and all advancement of the society we have today. Similar to how we continue to voyage into the unknowns of this world to find resources to supply for our needs, studies through new materials, species we encounter will all benefit the most common problems we have such as energy resource, medical needs and cure for the incurable diseases. These explanetary exploration may be the next key which holds potential to solve these problems.

5 0

4 years ago

Read 2 more answers

the battery of a car has a rating stated which permit you to estimate the length of time a fully charged battery could deliever

Lubov Fominskaja [6]

Answer:

600Joules

Explanation:

The energy stored by this battery is calculated using the energy formula;

E = Q× v

Where E is energy

Q is the charge

v is voltage

Hence E = 50 × 12 = 600Joules

Note Q = 12 ampere minute

5 0

3 years ago

A bus hits a bug and the bug splatters on the windshield, which force is greater?

grandymaker [24]

The forces acting on a body and the type of motion that results are given by Newton's three Laws of motion

The force of the bus is the same as reactive force of the bug

Reason:

According to Newton's third Law of motion, given that the bug collides

with the bus, the force with which the bus hits the bug is equal to the

reactive force of the bug on the on the bus

According to Newton's second Law of motion, force is equal to the rate of

change of the momentum produced

The impulse of the force of the bus on the bug is given as follows;

F·Δt = m·(v₂ - v₁)

Given that the force of the bus is large, the change in momentum, m·(v₂ - v₁),

is also large such that the parts of the bug are split by the rapid change in

velocity, and the bug splatters on the windshield, and is then carried along

on the trip,

The equally large reactive force of the bug, is such that the bug splatters

due its magnitude

Therefore, the correct response is that the forces are the same

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brainly.com/question/21279060

8 0

2 years ago

A rope is wrapped around the rim of a large uniform solid disk of mass 325 kg and radius 3.00 m. The horizontal disk is made to

Naily [24]

Answer:

The angular speed is 0.13 rev/s

Explanation:

From the formula

$\tau = I\alpha$

Where $\tau$ is the torque

$I$ is the moment of inertia

$\alpha$ is the angular acceleration

But, the angular acceleration is given by

$\alpha = \frac{\omega}{t}$

Where $\omega$ is the angular speed

and $t$ is time

Then, we can write that

$\tau = \frac{I\omega}{t}$

Hence,

$\omega = \frac{\tau t}{I}$

Now, to determine the angular speed, we first determine the Torque $\tau$ and the moment of inertia $I$ .

Here, The torque is given by,

$\tau = rF$

Where r is the radius

and F is the force

From the question

r = 3.00 m

F = 195 N

∴ $\tau = 3.00 \times 195$

$\tau = 585$ Nm

For the moment of inertia,

The moment of inertia of the solid disk is given by

$I = \frac{1}{2}MR^{2}$

Where M is the mass and

R is the radius

∴ $I = \frac{1}{2} \times 325 \times (3.00)^{2}$

$I = 1462.5$ kgm²

From the question, time t = 2.05 s.

Putting the values into the equation,

$\omega = \frac{\tau t}{I}$

$\omega = \frac{585 \times 2.05}{1462.5}$

$\omega = 0.82$ rad/s

Now, we will convert from rad/s to rev/s. To do that, we will divide our answer by 2π

0.82 rad/s = 0.82/2π rev/s

= 0.13 rev/s

Hence, the angular speed is 0.13 rev/s,

6 0

3 years ago