To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as
From the continuity equations in pipes we have to
Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,
From Bernoulli equation we have that the change in the pressure is
![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)
Therefore the speed of flow in the first tube is 0.9m/s
Answer:
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What type of reaction is being shown in this energy diagram
Above information helps you bro.
