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katen-ka-za [31]
3 years ago
11

It is cold and dry outside. You go down the slide and experience a small electric shock. What charge must you and slide be in or

der for that to happen?
A. you and the slide are negative which caused the shock B. you and the slide are positively charged which causes the shock C. the slide is positive and you are negative causing the electrons to jump to you and shock you o jump o D. nothing, you made it up in your head.
Physics
2 answers:
Simora [160]3 years ago
5 0
I think the answer is c or b
ruslelena [56]3 years ago
3 0

Answer:

c

Explanation:

the charge wants to ultimately balance out so either you or the slide gave the other electrons to balance the charges

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Charges flow from___<br> voltage to____<br> voltage.
iogann1982 [59]

Answer:

high to low

Explanation:

5 0
3 years ago
When you are using a crowbar to lift a large rock, you are working agents the force called
TEA [102]
When you're using a crowbar to lift a large rock, you are working against the force called

\boxed {\bf Gravity}


\bf Explanation:
Gravity on Earth is what gives weight to all objects, it's defined as all things that have mass or energy are gravitated towards each other. Therefore when you're using a crowbar to lift a large rock, the weight is caused by gravity.


I hope this helps you!
7 0
3 years ago
A 600-g block is dropped onto a relaxed vertical spring that has a spring constant k =190.0 N/m. The block becomes attached to t
charle [14.2K]

Answer:

Work done will be 2.205 j

Explanation:

We have given that the spring is compressed b 37.5 cm

So d = 0.375 m

Mass of the block m = 600 gram = 0.6 kg

Acceleration due to gravity g=9.8m/sec^2

Gravitational force on the block F=mg=0.6\times 9.8=5.88N

Now we know that work done is give by W=Fd=5.88\times 0.375=2.205J

5 0
3 years ago
please help! find magnitude and direction (the counterclockwise angle with the +x axis) of a vector that is equal to a + c
-BARSIC- [3]

Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

   = \sqrt{17.81+19.18}

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

6 0
3 years ago
If an antelope can run 14.1 km in 39 min, how fast is it km/h(for reference , 110 km/h is 65 mph )
shtirl [24]
It might make more sense putting it another way but this is basically it. you just take the minutes and divide them by 60 to convert them to hours. then simplify the ratio

8 0
3 years ago
Read 2 more answers
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