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dybincka [34]
3 years ago
11

Please help Thanks!!

Mathematics
2 answers:
kherson [118]3 years ago
8 0

Answer: 13

Step-by-step explanation:

erik [133]3 years ago
3 0

Answer:

13

Step-by-step explanation:

pythagorean theorem

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Please solve this,<br><br> x=1/(2-√3)<br> y=1/(2+√3)<br><br> x^4+y^4=?
Charra [1.4K]

Answer:4y

Step-by-step explanation:

6 0
3 years ago
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For a sample variance of n = 36 that has a sample variance of 1,296, what is the estimated error for the sample?
lukranit [14]

Answer:

6

Step-by-step explanation:

Given :

Sample size, n = 36

Sample variance, s² = 1296

The estimated standard error can be obtained using the relation :

Standard Error, S. E = standard deviation / √n

Standard deviation, s = √1296 = 36

S.E = 36/√36

S.E = 36/6

S.E = 6

Hence, estimated standard error = 6

7 0
3 years ago
Help asap I will give u huge amount of brainly points
Minchanka [31]

Answer:

\boxed{\sf -\dfrac{5}{8}}

Use BODMAS rule,

where:

  • brackets
  • order
  • division
  • multiplication
  • addition
  • subtraction

Given expression:

\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{4} \right)^2]

simplify exponent

\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{16} \right)]

\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{14}{16}]

\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{7}{8}]

\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{32}{8} -\(\dfrac{7}{8}]

\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{25}{8}]

multiply fractions

\rightarrow \sf -\dfrac{25}{40}

\rightarrow \sf -\dfrac{5}{8}

8 0
1 year ago
Read 2 more answers
What is the value of x in the isosceles trapezoid below? 4x+37=9x
erma4kov [3.2K]

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Step-by-step explanation:

8 0
3 years ago
True or​ false: when comparing two​ populations, the larger the standard​ deviation, the more dispersion the distribution​ has,
SOVA2 [1]

True, because the standard deviation describes how​ far, on​ average, each observation is from the typical value. A larger standard deviation means that observations are more distant from the typical​ value, and​ therefore, more dispersed.

6 0
3 years ago
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