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lozanna [386]
3 years ago
12

Twice the sum of a number and 7 is more than 6 or at most -3. Which compound inequality can represent this relationship

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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The law firm of Dewey, Cheetham, and Howe handled 18 personal injury cases this past year. This was 9/7 of the cases handled by
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Answer:

14 cases

Step-by-step explanation:

Let x be the number of personal injury cases this year by Gypsum Goode

x* 9/7 = 18

Multiply each side by 7/9

x * 9/7 *7/9 = 18 * 7/9

x = 14

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((-5)-(-7)-(-3))x(10)
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50

Step-by-step explanation:

{ (-5)-(-7)-(-3) } x10

{ (-5) +7 +3 } x 10

(-5 +10) x 10

5 x 10 = 50

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The city's central library has 72,864 books. The library has 72 bookcases. If each bookcase has room for the same number of book
sesenic [268]
1012 books per book case
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Helpp with math!!!!!!!!
grandymaker [24]

I think the area is 63. Sorry if it is incorrect.

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3 years ago
Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)
Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

x^2-2x + y^2 - 6y = 26

Typically, the equation of a circle would be in the form (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.

To get the given equation x^2-2x + y^2 - 6y = 26 into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

x^2-2x

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

x^2-2x+1

Great! Now, let's add this to our original equation:

x^2-2x+1+y^2-6y = 26

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27

Complete the square:

(x-1)^2+y^2-6y = 27

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation (x-1)^2+y^2-6y = 27:

y^2-6y

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

y^2-6y+9

Great! Now, back to our original equation:

(x-1)^2+y^2-6y+9= 27

Remember to add 9 on the other side as well:

(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36

Complete the square:

(x-1)^2+(y-3)^2= 36

<u>3) Determine the center and the radius</u>

(x-1)^2+(y-3)^2= 36

(x-h)^2+(y-k)^2=r^2

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0
3 years ago
Read 2 more answers
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