Answer:
There’s only one way to get 12 when 2 dice are tossed, both have to equal 6. There are 6 ways tossing a single die can come out (1,2,3,4,5,6), so if you toss dice, the second die could have any one of six values with each of the numbers that could result from the first toss (e.g., 1 from die 1 and 1,2,3,4,5, or 6 from die 2). So, considering there are 6 ways to fill each of two slots, there are 6 x 6 = 36 possible outcomes of tossing two dice. Only one of them equals 12, so p(12 given 2 dice tossed) = 1/36 = 0.02777777777778.
Answer:
$176
Step-by-step explanation:
$200 x 12%
12% --> 0.12
200 x 0.12 = 24 --> discounted off amount
200 - 24 = 176
Answer:
it should be 2 units
Step-by-step explanation:
what is the mean of this data set? 12, 17, 16, 10, 20, 13, 14, 14, 12, 12, 19, 18. answers: 13.50, 14.00, 14.75, and 15.75
murzikaleks [220]
Answer:
14.75
Step-by-step explanation:
Add them all up, divide by 12
Answer:






Step-by-step explanation:
Given

See attachment for proper table
Required
Complete the table
Experimental probability is calculated as:

We use the above formula when the frequency is known.
For result of roll 2, 4 and 6
The frequencies are 13, 29 and 6, respectively
So, we have:



When the frequency is to be calculated, we use:


For result of roll 3 and 5
The probabilities are 0.144 and 0.296, respectively
So, we have:


For roll of 1 where the frequency and the probability are not known, we use:

So:
Frequency(1) added to others must equal 125
This gives:


Collect like terms


The probability is then calculated as:


So, the complete table is:





