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antiseptic1488 [7]
4 years ago
12

Which of these would be an example of unbalanced forces?

Physics
2 answers:
masha68 [24]4 years ago
7 0

Your answer is:

D. A snowball picks up speed as it rolls down the mountain.

An unbalanced force is when 2 forces act on each other (they aren't equal and opposite). That makes them cause motion.

mylen [45]4 years ago
3 0

A snowball picks up speed as it rolls down the mountain.<em> (D)</em>

Since the description includes acceleration ("picks up speed"), we know that the forces on the snowball must be unbalanced.

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A girl is sitting in a sled sliding horizontally along some snow (there is friction present).
Over [174]

Answer:

159 N

Explanation:

The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then

Fr=0.25*636=159 N

Therefore, the force of friction is equivalent to 159 N

4 0
3 years ago
How do the particles in a solid move
ss7ja [257]
In a solid particles vibrate back and forth
7 0
3 years ago
Read 2 more answers
two objects were lifted by machine one object had a massive 2 kg it was lifted at a speed of 2 m/s the other had a massive 4 kg
rosijanka [135]
Kinetic energy =(1/2) (mass) (speed²)

First object:  KE = (1/2) (2 kg) (2m/s)² =  4 joules during the lift.

Second object:  KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.

The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
final heights and stop, neither object has any kinetic energy. 
8 0
3 years ago
in an automobile crash, a vehicle was stopped at a red light is rear-ended by another vehicle. The vehicles have the same mass.
Masja [62]

8 m/s

Explanation:

Using conservation of momentum :-

m1u1 + m2v1 = m1u2 + m2v2

Where:

m1 = Mass of first vehicle

m2 = Mass of second vehicle

u1 = initial speed of first vehicle

v1 = initial speed of second vehicle

u2 = Final speed of first vehicle

v1 = Final speed of second vehicle

From the received informations:

m1 = m2

v1 = 0

v2 = u2 = 4 \frac{m}{s}

So

m1u1 + 0 = 4m1 + 4m1

Now divide both sides by m1 :-

u1 = 4 + 4

u1 = 8m/s

Therefore, final answer is 8 m/s

4 0
3 years ago
Do subscripts and coefficient matter?
Serga [27]
UHHHHHH yes...... well depends on what the question is asking but more times then not  yes they matter. 
4 0
3 years ago
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