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GarryVolchara [31]
3 years ago
8

a concave mirror of radius of curvature 20cm produces an inverted image three times the size of an object placed on and perpendi

cular to the axis. calculate the position of the object and the image​
Physics
1 answer:
Elis [28]3 years ago
6 0

Answer:

Check attachment for your answer

Good luck

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Which action is due to field forces?
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an apple falling from a tree

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What is the speed of a cyclist that rides west 88 km in 32 minutes?
suter [353]

Answer:

The speed of the cyclist is 2.75 km/min.

Explanation:

Given

  • The distance d = 88 km
  • Time t = 32 minutes

To determine

We need to find the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

Using the formula involving speed, time, and distance

s=\frac{d}{t}

where

  • s = speed
  • d = distance covered
  • t = time taken

substitute d = 88, and t = 32 in the formula

s=\frac{d}{t}

s=\frac{88}{32}

Cancel the common factor 8

s=\frac{11}{4}

s=2.75 km/min

Therefore, the speed of the cyclist is 2.75 km/min.

8 0
3 years ago
Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. Use 6378km for the radius of
Radda [10]

According to the information provided to define an average density, it is necessary to use the concepts related to mass calculation based on gravitational constants and radius, as well as the calculation of the volume of a sphere.

By definition we know that the mass of a body in this case of the earth is given as a function of

M = \frac{gr^2}{G}

Where,

g= gravitational acceleration

G = Universal gravitational constant

r = radius (earth at this case)

All of this values we have,

g = 9.8m/s^2\\G  = 6.67*10^{-11} m^3/kg*s^2\\r = 6378*10^3 m

Replacing at this equation we have that

M = \frac{gr^2}{G} \\M = \frac{(9.8)(6378*10^3)^2}{6.67*10^{-11}} \\M = 5.972*10^{24}kg

The Volume of a Sphere is equal to

V = \frac{4}{3}\pi r^3\\V = \frac{4}{3} \pi (6378*10^3)^3\\V = 1.08*10^{21}m^3

Therefore using the relation between mass, volume and density we have that

\rho = \frac{m}{V}\\\rho = \frac{5.972*10^{24}}{1.08*10^{21}}\\\rho = 5.52*10^3kg/m^3

6 0
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