Answer:
Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.
Explanation:
The charge on the electron is 1.6x10^-19C. So, 10^24 of them will be a charge of 1.6x10^5C, F = q1xq2/[(4pi epsilon nought)r^2]
The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration.
F = 128N.
M = 35.2kg.
128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636
The acceleration is 3.636 m/s^2.
I hope this helps!
Answer:




Explanation:
r = Radius of disk = 7.9 cm
N = Number of revolution per minute = 1190 rev/minute
Angular speed is given by

The angular speed is 
r = 2.98 cm
Tangential speed is given by

Tangential speed at the required point is 
Radial acceleration is given by

The radial acceleration is
.
t = Time = 2.06 s
Distance traveled is given by

The total distance a point on the rim moves in the required time is
.
Answer:
D
friction acts in the opposite direction of motion but does not affect the motion of the object