Answer: idk
Step-by-step explanation: how am i supposed to know
Answer:
1/4
Step-by-step explanation:
use the slope formula, (y2-y1)/(x2-x1) , or rise over run.
this would give you 2-(-1) divided by 6-(-6)
giving you 3/12, reducing to 1/4
27202 - 3489 you can't do 2-9 so you cross out the 0 next to it and put it into a 10 and then turn your to into a 12 so 12 - 9 is 3 then since you have your 0 turned into 10 you do 10-8 you would you get 2 then you can't do 2-4 so we got the cross out your 7 next to it and turn that into a 6 then change 2 into 12 and then do 12 - 4 equals 8 then since you changed your 7
into a 6 6-3 would you get three and then you do 2-0 because there is no number there and you put down 23823 so 23823 is your answer
Answer:
<h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>36</u></em></h2>
Step-by-step explanation:
=> <em><u>x</u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>36</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
"Part A: What is the y-intercept of the function, and what does this tell you about the horse? (4 points)" The y-intercept is (0,8), which tells us that at the beginning the horse is 8 miles from the barn.
"Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)" The value of the function at x=1 is 58 and that at x=3 is 158. Thus, the change in the horse's distance from the barn is 158-58, or 100 feet. The time period involved here is 2 sec. Thus, the average rate of change of the horse's position with respect to time is
100 feet
average rate of change = ---------------- = 50 ft/sec
2 sec
If the horse were to move steadily at a fixed rate from 58 feet to 158 feet from the barn, its average rate would be 50 ft/sec.
"Part C: What would be the domain of the function if the horse continued to walk at this rate until it traveled 508 feet from the barn? (2 points)"
Here time begins at x=0 and ends at x=4 sec. Thus, the appropriate domain here is [0,4] sec.
