All categories

2 years ago

A rectangular shelf with an area equal to x^2-16x+60 square units could have which possible dimensions for length and width

Mathematics

1 answer:

kenny6666 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

x²-16x+60

=x²-6x-10x+60

=x(x-6)-10(x-6)

=(x-6)(x-10)

so dimensions are x-6 and x-10.

You might be interested in

h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l

mr Goodwill [35]

Answer:

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

Step-by-step explanation:

We are given that

$h(n)=-13n$

We have to find the recursive formula of h(n).

Substitute n=1

$h(1)=-13$

n=2

$h(2)=-13-13=-26=h(1)-13$

n=3

$h(3)=-13(3)=-39=-26-13=h(2)-13$

$h(4)=-13(4)=-52=-39-13=h(3)-13$

$h(n)=h(n-1)-13$

Therefore, the recursive formula is given by

h(1)=-13

$h(n)=h(n-1)-13, n\geq 2$

5 0

3 years ago

astra-53 [7]

Answer:

ABC is similar to DEF

ABC is similar to DFE

Step-by-step explanation:

6 0

3 years ago

What is 3 multiplied by 3/8 as a mixed number

krek1111 [17]

Answer:

1 and 1/8

Step-by-step explanation:

The number 1.125 can be writen using the fraction 1125/1000 which is equal to 9/8 when reduced to lowest terms.

It is also equal to 1 1/8 when writen as a mixed number.

You can use the following approximate value(s) for this number:

1.125 =~ 1 (if you admit a error of -11.111111%)

7 0

3 years ago

HELP PLEASE I NEED IT ASAP

Akimi4 [234]

Answer:

849.9 cm squared

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Rewrite the system of linear equations as a matrix equation AX = B.

iren2701 [21]

Answer:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]$

And the vector of vriables (X) is:

$\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]$

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

$\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

In conclusion, AX=B is:

$\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]$

7 0

3 years ago