Answer:
5 (strawberries / hours)
Step-by-step explanation:
calculation fro morning
strawberries / minutes x minutes / hours = strawberries / hours
so after adding the value in above equation
3/4* 60/1 = 45 strawberries / hours
calculation in the afternoon
strawberries / minutes x minutes / hours = strawberries / hours
2/3 x 60/1 = 40 strawberries / hours
so now by calculating difference between morning and afternoon packing rates, you can easily calculate
45-40 = 5 (strawberries / hours)
Answer:
Step-by-step explanation:
a. The hypothesis test is one tailed_____ test.
(Because we check whether sample weight is greater than hence one tailed or right tailed)
The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)
The value of the test statistic is___Mean difference/Std error =
__
b. df = 66
Reject H0 if t ≥ 1.668
c. The p-value is_____0.059444
d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.
CosA = 12/20 which is 3/5
X=-10 m= 6 that is what I think