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alex41 [277]
3 years ago
14

Solve 2х2 – 3х – 3 = 0

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
The answer to this question is X= 1/2
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2481.7

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The 5 would either round it up or down by one-tenth. Since we like big numbers... we'll round it to 7 from 6.

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Find the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)
Eva8 [605]

The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is (\frac{-17}{5} ,\frac{2}{5} )

Explanation :

the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)

Apply section formula to find coordinates of point Q

(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n} )

Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)

Substitute all the values inside the formula

(\frac{2(2)+3(-7)}{2+3} , \frac{2(4)+3(-2)}{2+3} )\\\\(\frac{-17}{5} ,\frac{2}{5} )

The coordinates of point Q is (\frac{-17}{5} ,\frac{2}{5} )

Learn more :  brainly.com/question/13878373

7 0
3 years ago
PLEASE HELP
lilavasa [31]

Those two functions just miss each other so there are no real solutions.  Every polynomial with complex coefficients has complex solutions.

2x^2 + 2 = 3x

2x^2 - 3x = -2

2( x^2 - \frac 3 2 x) = -2

x^2 - \frac 3 2 x = -1

x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2

(x - \frac 3 4)^2 = -\frac 7{16}

x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}

x = \frac 3 4 \pm \frac i 4 \sqrt{7}

x = \frac 1 4(3 \pm i \sqrt{7})


4 0
3 years ago
Jamal started 10 yards from the end zone
Tatiana [17]

There is no equation?

7 0
4 years ago
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