What division problem can be represented using the number line?
1 answer:
You might be interested in
An exponent is a number written above and to the right side of a value or number in math. The value or number is called the base, and the expression is read out as;
"Base raised to the power of exponent."
An example is given below;
In this example, 10 is the base and 3 is the EXPONENT.
The expression is now read out as,
"10 raised to the power of 3"
Note that even unknown values (such x as we commonly use in math) can also be an exponent or base. For example, we can have;
So basically, an exponent indicates the number of times a number is used to multiply itself.
Answer:
6
Step-by-step explanation:
We want to evaluate:
8a-1+0.5b
When a=1/4 and b=10.
We simply substitute the given values of as and b into the given expression,
The value of the expression is 6 for the give values of a and b.
The <u>correct answer </u>is:
x²+2x+3.
Explanation:
We need to divide each term of the numerator by the denominator. For the <u>first term</u>:
Dividing the coefficients, we have 5/5 = 1.
When dividing the variables, we use the quotient rule: when dividing powers that have the same base, subtract the exponents. This gives us:
x³/x = x³/x¹ = x³⁻¹ = x²
For the first monomial, this gives us 1x² = x².
The <u>second term</u>:
Dividing the coefficients, we have 10/5 = 2.
Dividing the variables, we again use the product rule:
x²/x = x²/x¹ = x²⁻¹ = x¹ = x
Together this gives us 2x.
The <u>third term</u>:
Dividing the coefficients, we have
15/5 = 3.
Dividing the variables, we have x/x; when you divide something by itself, the answer is 1. This gives us:
3*1 = 3.
Together our quotient is x²+2x+3.
x²+2x+3.
Explanation:
We need to divide each term of the numerator by the denominator. For the <u>first term</u>:
Dividing the coefficients, we have 5/5 = 1.
When dividing the variables, we use the quotient rule: when dividing powers that have the same base, subtract the exponents. This gives us:
x³/x = x³/x¹ = x³⁻¹ = x²
For the first monomial, this gives us 1x² = x².
The <u>second term</u>:
Dividing the coefficients, we have 10/5 = 2.
Dividing the variables, we again use the product rule:
x²/x = x²/x¹ = x²⁻¹ = x¹ = x
Together this gives us 2x.
The <u>third term</u>:
Dividing the coefficients, we have
15/5 = 3.
Dividing the variables, we have x/x; when you divide something by itself, the answer is 1. This gives us:
3*1 = 3.
Together our quotient is x²+2x+3.