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Amanda [17]
3 years ago
6

What is the Answer. ​

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

18

Step-by-step explanation:

4x+100+3x+79=32

7x+179=32

7x=-147

x=-21

Now, plug in the numbers.

3(-21)+79=-61+79

=18

Hope I helped! Please mark Brainliest!!!

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XD no sé que decir E=mc2 lo siento.

4 0
3 years ago
Solve 7x - 8 = 3x + 40
Contact [7]

Answer:

7x-8=3x+40\\7x-3x=40+8\\4x=48\\x=12

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Divide -6/7 by 2/-3 please give answer very fast its urgent
defon

Answer:

0.14285714285

Step-by-step explanation:

divide on calculator and make sure to have negative sign before three, remember you are dividing fractions

I hope it helps! If not sorry :(

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3 years ago
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An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
2 years ago
Fill in the blank <br><br><br><br><br> …………………..
Mumz [18]
So uhh I’m so sorry to tell you but I don’t know how to do math myself and I just need points so I’m answering this.. but I’m sure If you just cheat off a smart person in your class you’ll be fine. If you need any tips on how to cheat lmk I’ll gladly help
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2 years ago
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