2 years ago

Given the following isotopes of strontium, calculate the average atomic mass.

Chemistry

1 answer:

vodka [1.7K]2 years ago

3 0

Answer:

87.5198

Explanation:

(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98

8751.98 / 100 = 87.5198

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A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

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Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

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