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ladessa [460]
3 years ago
6

A chemist adds of a M copper(II) fluoride solution to a reaction flask. Calculate the mass in micrograms of copper(II) fluoride

the chemist has added to the flask. Round your answer to significant digits.
Chemistry
1 answer:
anygoal [31]3 years ago
7 0

The question is incomplete, here is the complete question.

A chemist adds 345.0 mL of a 0.0013 mM (MIllimolar) copper(II) fluoride CuF_2 solution to a reaction flask.

Calculate the mass in micrograms of copper(II) fluoride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer : The mass of copper(II) fluoride is, 0.13 mg

Explanation :  Given,

Millimolarity of copper (II) fluoride = 0.0013 mM

This means that 0.0013 millimoles of copper (II) fluoride is present in 1 L of solution

Converting millimoles into moles, we use the conversion factor:

1 moles = 1000 millimoles

So, 0.0013mmol\times \frac{1mol}{1000mmol}=1.3\times 10^{-6}mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Moles of copper (II) fluoride solution = 1.3\times 10^{-6}mol

Molar mass of copper (II) fluoride = 101.5 g/mol

Putting values in above equation, we get:

1.3\times 10^{-6}mol=\frac{\text{Mass of copper (II) fluoride}}{101.5g/mol}\\\\\text{Mass of copper (II) fluoride}=(1.3\times 10^{-6}mol\times 101.5g/mol)=1.32\times 10^{-4}g

Converting this into milligrams, we use the conversion factor:

1 g = 1000 mg

So,

\Rightarrow 1.32\times 10^{-4}g\times (\frac{1000mg}{1g})=0.13mg

Therefore, the mass of copper(II) fluoride is, 0.13 mg

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<h3><em>Further Explanation</em> </h3>

Significant numbers are numbers obtained from the measurement results of exact numbers and the last number estimated

In scientific notation, all numbers are displayed before the big order is called significant numbers

the scientific notation can be described as:

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In the question it is known that (2.5 × 10¹⁰) and (3.5 × 10⁻⁷) both have a significant number in a row 2.5 and 3.5

so that it meets the rule of significant numbers which is multiplication of 2 significant number produces numbers that have the fewest significant numbers,  So the multiplication of the two will produce 2 significant number

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So the result = 8.75.10³

Because the result must have 2 significant number , the result is 8.8.10³ (8.75 we round up)

<h3><em> Learn more</em></h3>

significant figures brainly.com/question/11151926

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the number of significant figures is 0.025 brainly.com/question/10343704

0.080 significant figures brainly.com/question/1999241

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