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yawa3891 [41]
4 years ago
5

Can anybody help me with these 2 ohms law

Chemistry
1 answer:
Fynjy0 [20]4 years ago
3 0

Answer:

1

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The diagram and data below represent gas and the conditions of pressure, volume, and temperature of the gas in a rigid cylinder
Sedaia [141]

Answer:

2.3 L

Explanation:

when you have this eqaution you use P1V1T2=P2V2T1.

since you are looking for volume of gas cylinder that means you are looking for V2.

so you have your given P= 1.0 atm, V=2.5L, T=298K.

They ask you to use STP or standard pressure and temperature.

STP P= 1atm, STP T=273 K

so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2

so you now substitue so its now 1*273*2.5/ 1* 298= V

682.5/ 298= V

Lastly V= 2.2902 and you round to tenths so now you have

V= 2.3 L

5 0
3 years ago
Which of the following gases would be most likely to experience ideal behavior at high pressures?
monitta
<span>Which of the following gases would be most likely to experience ideal behavior at high pressures? 
a. F2 
b. Ne 
c. C2H6 

Yes. The answer is (b) Ne (Neon). This is because monoatomic gases such as neon do not experience </span><span>intermolecular attractions and thus most likely to be close to ideal gases behavior. Not only that, Neon is a noble gas and is unreactive. </span>
5 0
4 years ago
Could anyone help me please and thanks on some of my questions im taking a unit test and i need to pass it... if anyone can plea
erastovalidia [21]
You're right, it's a solid at room temperature :)
7 0
4 years ago
Match the answer please
Triss [41]

Answer:

1- mindset

2-set backs

3-tendonitis

4-enviorment

5-rehabilitable

6-self montitering

HOPE I HELPED

∫∫-depree

3 0
3 years ago
In the operation of the Heat Transfer Service Unit, one of the variables you can control is the rate of cooling water flowing ag
max2010maxim [7]

Answer:

A. The rate of heat transfer through the material would increase.

Explanation:

To calculate the heat transfer in a heat exchanger you decide that there is not heat leakage to the surroundings, that means that  magnitude of the two transfer rates will be equal. Any heat lost by the hot fluid, is gained by the cold fluid. The equation that describes this is Q = m×Cp×dT

Where:

heat = mass flow ×specific heat capacity × temperature difference

So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.

5 0
3 years ago
Read 2 more answers
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