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oee [108]
4 years ago
8

Solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. Write the balanced chemical equation for the

reaction described. Phases are optional.
Chemistry
1 answer:
Bess [88]4 years ago
5 0

Answer:

Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)

Explanation:

The <u>formula</u> for iron (II) hydroxide is Fe(OH)_2

The <u>formula</u> for iron(II) oxide is FeO

The <u>formula</u> for liquid water is H_2O

The <u>reaction</u> would be:

Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)

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Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

(D) MgSO_4

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}

So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

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Match each lab incident to the item of PPE that will protect you from it. Each item of PPE will only be used once.
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Answer:

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