For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.
From the problem, you know that 1) = 2.000 g.
Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).
1) = 5.022 g - 3.715 g = 1.307 g
Now you can complete our original task.
Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.
Answer:chlorofluorocarbons (CFCs)
halon.
carbon tetrachloride (CCl4)
methyl chloroform (CH3CCl3)
hydrobromofluorocarbons (HBFCs)
hydrochlorofluorocarbons (HCFCs)
methyl bromide (CH3Br)
bromochloromethane (CH2BrCl)
Explanation:
BRAINLIEST pls
Answer:
substance*? a particular kind of matter with uniform properties.
Explanation:
Answer:
it's lead (ii) nitrate the name
Answer:
3. doubles
Explanation:
for an ideal gas behavior, the relationship between volume and temperature is given by Charles law
Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as
V ∝ T
V=KT
K = V/T
where V is the volume of the gas
T is the Temperature
k represents the constant of proportionality
For initial and final conditions of a gas,
= 
where 1 and 2 represent initial and final conditions respectively
therefore, T₁ = 100 and T₂ = 200
= 
200 × V₁ = 100 × V₂
divide both sides by 100
2V₁ = V₂
final volume,V₂ = 2V₁
there the volume doubles