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oee [108]
3 years ago
8

Solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. Write the balanced chemical equation for the

reaction described. Phases are optional.
Chemistry
1 answer:
Bess [88]3 years ago
5 0

Answer:

Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)

Explanation:

The <u>formula</u> for iron (II) hydroxide is Fe(OH)_2

The <u>formula</u> for iron(II) oxide is FeO

The <u>formula</u> for liquid water is H_2O

The <u>reaction</u> would be:

Fe(OH)_2_(_s_)~->~FeO_(_s_)~+~H_2O_(_l_)

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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<u>Step 2: Identify Conversions</u>

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<u>Step 4: Check</u>

<em>Follow sig figs and round. We are given 2 sig figs.</em>

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