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zmey [24]
3 years ago
6

Solve the inequality for W: 5W - 23 < - 3 (3 - 4W)

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
5w−23<−3(3−4w)

Simplify both sides of the inequality.

5w−23<12w−9

Subtract 12w from both sides.

5w−23−12w<12w−9−12w

−7w−23<−9

Add 23 to both sides.

−7w−23+23<−9+23

−7w<14

Divide both sides by -7.

−7w/−7 < 14/−7

w > −2

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If P = 4x^4 - 3x^3 + x² - 5x + 11 and Q = -3x^4 + 6x^3 - 8x² + 4x - 3, what is P - 2Q?
vazorg [7]

Answer:

10x^4-15x^3+17x^2-13x+17

Step-by-step explanation:

P-2Q

Replace P and Q with the given values,

4x^4-3x^3+x^2-5x+11-(2(-3x^4+6x^3-8x^2+4x-3)

4x^4-3x^3+x^2-5x+11-(-6x^4+12x^3-16x^2+8x-6)

4x^4-3x^3+x^2-5x+11+6x^4-12x^3+16x^2-8x+6

10x^4-15x^3+17x^2-13x+17

7 0
2 years ago
Swimming Pool On a certain hot​ summer's day, 143 people used the public swimming pool. The daily prices are $ 1.25 for children
kramer

Answer: 102 children and 41 adults swam at the pool that day.

Step-by-step explanation:

Let x represent the number of children that swam at the public pool that​ day.

Let y represent the number of adult that swam at the public pool that​ day.

On that certain hot​ summer's day, 143 people used the public swimming pool. It means that

x + y = 143

The daily prices are $1.25 for children and $2.25 for adults. The receipts for admission totaled $219.75. It means that

1.25x + 2.25y = 219.75- - - - - - - - -1

Substituting x = 143 - y into equation 1, it becomes

1.25(143 - y) + 2.25y = 219.75

178.75 - 1.25y + 2.25y = 219.75

- 1.25y + 2.25y = 219.75 - 178.75

y = 41

x = 143 - y = 143 - 41

x = 102

5 0
3 years ago
I need help with algebra 9
Leona [35]

Answer:

i got you just tell me the question

Step-by-step explanation:

3 0
3 years ago
If Colorado Springs, Colorado, has 1.6 times more days of sunshine than Boston, Massachusetts, how many days of sunshine does ea
Kay [80]
C = 1.6b
c + b = 442

1.6b + b = 442
2.6b = 442
b = 442 / 2.6
b = 170 <== Boston

c = 1.6b
c = 1.6(170)
c = 272 <== Colorado Springs
8 0
3 years ago
Geometry question for homework.
mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0
3 years ago
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