Basically, we need to find the diagonal of the square. Once we have the diagonal, we need to find if it's more or less than 11 cm, which is diameter of the circle.
This is the formula we'll use:
a²+b²=c²
Since it's a square, a and b are the same.
7²+7²=c²
49+49=c²
98=c²
√98=c
c=9.8995
So, the diagonal is 9.8995
9.8995<11
So, since the diagonal of the square is 9.8995 cm, it is less than the circumference of the circle meaning that it will fit in to the circle without touch the circle's circumference.
Answer:
1/4
Step-by-step explanation:
Answer:
y = 2x + 13
y = –x – 2
Step-by-step explanation:
The options are:
y = 2x + 13
y = -x - 2
y = 3x - 5
y= -(1/2)x + 6
y = -2x - 2
The graph is shown in the figure attached. There, point (-5, 3) is shown. Replacing it into the equations we get:
y = 2(-5) + 13 = 3 (so, it is a solution)
y = -(-5) - 2 = 3 (so, it is a solution)
y = 3(-5) - 5 = -20 ≠ 3 (so, it isn't a solution)
y= -(1/2)(-5) + 6 = 8.5 ≠ 3 (so, it isn't a solution)
y = -2(-5) - 2 = 8 ≠ 3 (so, it isn't a solution)
Answer:
Area of the base of the pyramid = V/h
Step-by-step explanation:
Mathematically, we know that the volume of the pyramid can be calculated by multiplying the area of the base by the height of the pyramid
Now using the variables in the question;
V = area of base * height of pyramid
Area of base = V/height of pyramid
Area of base = V/h
