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melomori [17]
3 years ago
9

How did the Buddha achieve enlightenment? *

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

B) he meditated

Step-by-step explanation:

according to BBC

One day, seated beneath the Bodhi tree (the tree of awakening) Siddhartha became deeply absorbed in meditation, and reflected on his experience of life, determined to penetrate its truth.

He finally achieved Enlightenment and became the Buddha. The Mahabodhi Temple at the site of Buddha's enlightenment, is now a pilgrimage 

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20

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How many terms of the arithmetic series 3+9+15.... will add up to 19200?​
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32 005

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4 0
2 years ago
Simplify, state all restrictions.
Kipish [7]

The simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Rewrite the expression as products

\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Cancel out the common factors

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1

Express 4x^2 - y^2 as (2x - y)(2x + y)

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1

Cancel out the common factors

\frac{1}{x + y} -1

Take the LCM

\frac{1 - x - y}{x + y}

Hence, the simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

Read more about expressions at:

brainly.com/question/723406

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7 0
2 years ago
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Answer:

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Step-by-step explanation:

I hope this helps.

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