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Tresset [83]
3 years ago
12

HELP!! correct answer gets brainliest

Mathematics
1 answer:
Llana [10]3 years ago
3 0

Answer:

1/3 I think I did the math and if that's not right try 1/3:1/4 (<--ratio)

Step-by-step explanation:

You might be interested in
Is c=$75x an equation if not how would i turn this into an equation.
spin [16.1K]
It is an equaiton because there is an 'equals' sign
it expresses equality
c is equal to 75 times x
it expresses equality
7 0
3 years ago
A bride and groom both invited guests to their wedding. The bride invited twice as many women as the groom did, and the groom in
n200080 [17]

Answer:

option 1) 50

Step-by-step explanation:

Let m and w denote the men and women respectively.

From the question, if the groom invited w number of women, then bride invited 2w number of women.

Also, if the bride invited m number of men,then the groom invited 2m.

Hence we can write the following maths equation:

w+2m=105.........1

2w+m=135.........2

We multiply eqn(1) by 2 to get eqn(3)

This implies that,

2w+4m=210.......3

We then subtract eqn (2) from eqn(3) to obtain;

3m=75

we divide through by 3

\implies \frac{3m}{3} = 75

\implies m= 25

Substituting the value of m into eqn (1)

to find the value for w

\implies w + 50 = 105

subtracting 50 from both sides.

\implies w + 50  - 50= 105 - 50

\implies w+2(25)=105

\implies w= 55

So we can say the :

bride invited 25 men and 110 women,

groom invited 50 men and 55 women.

6 0
3 years ago
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
3 years ago
Read 2 more answers
What is the answer to -6 2/3 - -8 1/5
zvonat [6]
14 2/8 should probably be your answear
7 0
3 years ago
(84x - 69y) - (65x + 34y)
Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

Combine for final answer:

19x -103y

6 0
3 years ago
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