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3 years ago

8

If x equals 8 what is the volume.

2 answers:

jolli1 [7]3 years ago

5 0

Hey There! Allow me to explain how to solve this (I will not say the answer bc I also don't know but here is how you can find it). As you see the shape is a Cyclinder & the formula for it is V=Bh or V=πr2h. You might wanna start with solving the problems (8x - 4) & (11x + 12) Use the order of PEMDAS (Parrenthesis, Exponets, Multiplication, Division, Addition, Subtraction.) to solve is so if solving (8x - 4) And if x = 8 than first begin with mutiliplying 8 x 8 (Because it says 8x and x = 8 which means we are multiplying) than subtract that with 4 (Which will be 64 - 4). Than for (11x + 12) you will wanna do 11 x 8 which is 88 added by 12 which that will be 100. Than use the formula (V=Bh or V=πr2h) And you should have you're answer! I hoped this help and sorry for not finding the answer but atleast I explained to you on how to solve it! <3

evablogger [386]3 years ago

3 0

Answer:

I think it might be 9420 Im not sure though

Step-by-step explanation:

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Nata [24]

Answer:

obtuse angled triangle

Step-by-step explanation:

one angle is more than 90

3 0

2 years ago

Thanks for the help! i dont really understand numbers with letters easily : )

jok3333 [9.3K]

Answer: x=6

Step-by-step explanation: Hope this help :D

4 0

3 years ago

HELP!!!!!! ILL GIVE BRAINLEST

Kobotan [32]

Answer:

Its 95/100

Step-by-step explanation:

7/10 can be changed into 70/100 then just add 25/100 and you get 95/100

4 0

3 years ago

Read 2 more answers

Write the equation of the line in slope-intercept form that has: slope: 3<br> point: (0,2)

goldenfox [79]

Answer:

y=3x+2

Step-by-step explanation:

y=mx+b

we have m here so

y=3x+b

then the 2 is the y-intercept

y=3x+2

7 0

3 years ago

NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago