Hey! First of all, you can express x squared as x^2.
Secondly, the problem! I'm assuming you're asking for the values of x - if you're asking what the equation is, it's a quadratic equation, or a second-degree polynomial. Solving for x, this equation can be factored as (x-4)(x+1)=0. Because either of these two terms being zero will make the whole equation zero, we can have x-4=0, in which case x=4, or x+1=0, in which case x=-1. Therefore, x is either 4 or -1
Answer:
a. 
b. 10
Step-by-step explanation:
= 100 -> so 100*0.005= 5
if you still dont understand search up "scientific notation"
Answer:
Step-by-step explanation:
The point slope form of a line is 
where 
. We write
Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.
Answer:
64.1
Step-by-step explanation:
You use Pythagorean theorem which is x^2 +y^2=z^2 (^ this means to the power of) so you would get 55^2+33^2=z^2. solving this would get you z=64.1404708433 or 64.1
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
