Plz help i dont have much time
2 answers:
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Answer:
<em>Surface area of the roof of the kennel, including the bottom face is 58.96 ft^2</em>
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Step-by-step explanation:
The image is attached below
For the triangular sides of the roof, area is
A =
where b is the base = 4 ft
h is the vertical height = 2.24 ft
A = 4.48 ft^2
for the two faces we have 2 x 4.48 ft^2 = <em>8.96 ft^2</em>
For the rectangular sections of the roof, area is
A =
where is the length of the rectangle = 5 ft
h is the height of the rectangle = 3 ft
A = 5 x 3 = 15 ft^2
For the two rectangular faces, we have 2 x 15 ft^2 = <em>30 ft^2</em>
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For the bottom face, area is
A =
where is the length of the house = 5 ft
w is the width of the house = 4 ft
A = 5 x 4 = <em>20 ft^2</em>
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Surface area of the roof of the dog kennel is
<em>8.96 ft^2 + 30 ft^2 + 20 ft^2 = 58.96 ft^2</em>
Answer:
625 ft^2
Step-by-step explanation:
Given
--- perimeter
Required
The largest area
The perimeter is calculated as:
So, we have:
Divide both sides by 2
Make L the subject
The area is calculated as:
Substitute
Open bracket
Differentiate with respect to W
Set to 0; to get the maximum value of W
Collect like terms
Divide by -2
So, the maximum area is: