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Doss [256]
2 years ago
7

Plz help i dont have much time

Mathematics
2 answers:
yawa3891 [41]2 years ago
5 0

1: 5

2: -28

3: 10.4

4: 0.875

5: 0

6. 8,003

5 techincally should be nonzero but I assume 0 is what the teacher is looking for.

Kryger [21]2 years ago
3 0

Answer:

I believe it's asking for the additive inverse so,

1. 5

2. -28

3. 10.4

4. -0.875

5. 0

6. 8,003

Step-by-step explanation:

hope this is what u need

if it's right pls mark brainleist

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Hi,
The like terms are 2xy, -xy and (1/2)xy, since they have the same variables and powers.
4 0
3 years ago
What is the amount of down payment on the house that cost $65,250? ​
Zarrin [17]
Depends on how much percent you have to put down for the house. Like if it’s 10% then just subtract 10% from the cost of the house.
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2 years ago
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The function a represents the cost of manufacturing product A, in hundreds of dollars, and the function b represents the cost of
PSYCHO15rus [73]

The answer is c)

Here’s why:

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3 years ago
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A carpenter is framing a wall that is 8 feet high and 15 feet long. If the carpenter wants to be sure that the sides of the wall
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If you cut the rectangle (the wall) diagonally, you get two congruent triangles. The measurements of the sides of one the triangles is 8, 15 and x. There is a pythagorean triples 8, 15, 17 so x has to be 17. if you dont know the triple you can do a^2 + b^2 = c^2         8^2 + 15^2 = c^2     c = 17

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The side length of each square is 6 units. Find the areas of the inscribed shapes.
kirill [66]

By using subtraction of <em>yellow</em> areas from the <em>entire</em> squares, the areas of the <em>inscribed</em> shapes are listed below:

  1. 18 units
  2. 20 units
  3. 12 units
  4. 12 units

<h3>How to calculate the areas of the inscribed shapes</h3>

The areas of the <em>inscribed</em> shapes can be easily found by subtracting the <em>yellow</em> areas from the square, in order to find the value of <em>green</em> areas. Now we proceed to find the result for each case by using <em>area</em> formulae for triangles:

Case A

A = 6² - 0.5 · (3) · (6) - 0.5 · (3) · (6)

A = 36 - 18

A = 18 units

Case B

A = 6² - 4 · 0.5 · (2) · (4)

A = 36 - 16

A = 20 units

Case C

A = 6² - 0.5 · 6² - 0.5 · 6 · 2

A = 36 - 18 - 6

A = 12 units

Case D

A = 6² - 2 · 0.5 · 6 · 4

A = 36 - 24

A = 12 units

To learn more on inscribed areas: brainly.com/question/22964077

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4 0
2 years ago
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