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AnnZ [28]
3 years ago
7

Which graph represents a decreasing function?

Mathematics
2 answers:
frozen [14]3 years ago
6 0
If its <span>decreasing it would be C because your line is going down</span><span />
Zinaida [17]3 years ago
6 0
<span>Graph A represents a constant function; when x increases: y still the same (no change).

</span>Graph B <span>represents a growing function, when x increases , also y increases.
</span>
Graph C represents a decreasing <span>(decay) function becasue when x increases, y decreases.

and for  </span>Graph D, it is not even a function .


So it would be: Graph C



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The secret number has a 7 in the ones place. The tens number is an odd number
Lana71 [14]
This really is left up to you as long as you have an odd number in the tens place and a 7 in the ones place. How big (or small) the number is is up to you. As long as it is at least 17, it's pretty much up to you.
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The graph of ƒ(x) = -√x is shifted to the right five units. The domain of the function represented by this graph is x ≥&gt;≤&lt;
Mars2501 [29]

Answer:

Domain = [5,∞)

Step-by-step explanation:

Given: f(x)=-\sqrt{x}

We are given that f(x) is shifted right by 5 units.

Rule : f(x)→f(x-b)

The graph f(x) shifted b units right

So, using rule : -\sqrt{x} →   -\sqrt{x-5}

So, g(x)=-\sqrt{x-5}

Now to find domain:

x-5>0

x>5

So, Domain = [5,∞).

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3 years ago
Write the equation of the parabola in vertex form.
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~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = a(x-0)^2+0\qquad \stackrel{\textit{we also know that}}{x=2\qquad y = 1}\qquad \implies 1=a(2-0)^2+0 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hspace{10em} \boxed{y=\cfrac{1}{4}x^2}

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HURRY WILL GIVE BRAINLIEST
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3 years ago
Read 2 more answers
A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.21, the probabil
WITCHER [35]

Answer:

2.65 dollars

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x1P(x1) + x2P(x2) + ... + xnP(xn)

Where x1, x2, ... , xn are the possibles values of the variable and P(x1), P(x2), ... , P(xn) are the probabilities of x1, x2, ... , xn respectively.

In this case, the roll can comes up 1, 2, 3 or 4 and you can win 1, 2, 3 or 4 dollars respectively. So, taking into account that they are mutually exclusive events, the probability that the player win 1, 2, 3 or 4 dollars is:

P(1) = 0.21

P(2) = P(1∪2) - P(1) = 0.42 - 0.21 = 0.21

P(3) = P(2∪3) - P(2) = 0.51 - 0.21 = 0.3

P(4) = 1 - P(1) - P(2) - P(3) = 1 - 0.21 - 0.21 - 0.3 = 0.28

Therefore, If you win the amount that appears on the die the expected winning are:

E(x) = $1P(1) + $2P(2) + $3P(3) + $4P(4)

E(x) = $1(0.21) + $2(0.21) + $3(0.3) + $4(0.28)

E(x) = $2.65

4 0
3 years ago
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