When put in matrix form, the coefficients of
... 3x -2y = 7
... x + 4y = 2
look like
![\left[\begin{array}{cc}3&-2\\1&4\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-2%5C%5C1%264%5Cend%7Barray%7D%5Cright%5D%20%20)
The determinant is 3×4 - 1×(-2) = 14.
This equation is written in <em>standard form</em>, so we need to change it into <em>slope-intercept form.</em>
<em />
3x = -y - 5
3x + y = -y + y - 5
3x + y = -5
3x - 3x + y = -5 - 3x
y = -5 - 3x
y = -3x - 5
The slope is classified as "m" in this type of equation, so, the slope is -3.
Best of Luck!
For this case what we must do is define h (x), which is given by:
h (x) = f (x) * g (x)
Where,
f (x) = 5 (The number of fish breeding farms)
g (x) = 80 (1.04) ^ x (The approximate number of fish per breeding farm)
Substituting we have:
h (x) = (5) * (80 (1.04) ^ x)
Rewriting we have:
h (x) = 400 (1.04) ^ x
Answer:
the approximate population of the fish across all Mr. Dawson's farms after x months is:
h (x) = 400 (1.04) ^ x
Pemdas
Parentheses
Answer: -11
Let
x--------->number of products
y1--------> <span>the cost of producing a product
y2------> </span><span>the cost of sell a product
</span><span>
we know that
y1=120,000+20x-------> equation 1
y2=50x------> equation 2
equate equation 1 and equation 2
120,000+20x=50x
50x-20x=120,000
30x=120,000
x=4000
the answer is
4000 pieces</span>
