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lesantik [10]
3 years ago
15

How did adding mushrooms affect trees?

Physics
1 answer:
artcher [175]3 years ago
7 0
How did adding mushrooms affect trees? A few of the trees decreased . Mushrooms are the fruiting structures of fungi, and many fungi are capable of damaging trees. ... The mushrooms are decomposers they thrive off of dead things including the trees so they do not harm the tress at all.
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A skier with a mass of 63 kg starts from rest and skis down an icy (frictionless) slope that has a length of 50 m at an angleof
victus00 [196]

Answer:

Explanation:

When the skier reaches the bottom of the slope , height lost by it

h = 50 sin32 m

= 26.5 m

potential energy lost

= mgh

Gain of kinetic energy

= 1/2 mv²

mgh = 1/2 mv²

v = √ 2gh

= √ (2x9.8 x 26.5)

= 22.8 m /s

b )

Let μ be the coefficient of kinetic friction required.

friction force acting

= μmg

work done by friction in displacement of  d (40 m ) on horizontal surface

- μmg x d

This negative work will be equal to positive kinetic energy of the skier on horizontal surface .

=  μmg x d  = (1/2) m v²

μ = v² / (2 gd)

= 519.4 / (2 x 9.8 x 140 )

= .19

8 0
4 years ago
A chart showing the type of reproduction that occurs in several organisms is shown below. Organism Type of Reproduction Bacteria
quester [9]

Answer:

C

Explanation:

7 0
3 years ago
Read 2 more answers
A 5.0 mm diameter proton beam carries a total current of 1.5mA. The current density in the proton beam, which increases with dis
slavikrds [6]

Answer:

Jedge = 0.076A/cm^2

Explanation:

If you want to know what is Jedge is convenient to use an integral. The total density current is given by:

J_T=\int_{0}^{R}J_{edge}(\frac{r}{R})dr=J_{edge}(\frac{1}{R})(\frac{R^2}{2})=\frac{J_{edge}R}{2}  (1)

But also, we have that the total current is

I_T=J_TA\\\\J_T=\frac{I_T}{A}=\frac{1.5*10^{-3}A}{\pi(5*10^{-3})^2}=19.09\frac{A}{m^2}

where we have used that 5mm=5*10^{-3}m.

By replacing (1) we obtain:

J_{edge}=\frac{2J_T}{R}=\frac{2(19.09A/m^2)}{5*10^{-3}m}=7639.4\frac{A}{m^2}=0.076\frac{A}{cm^2}

hope this helps!!

3 0
4 years ago
Read 2 more answers
The index of refraction of a type of glass is 1.50, and the index of refraction of water is 1.33. If light enters water from thi
Damm [24]

Answer:

Option C - the angle of refraction is greater than the angle of incidence

Explanation:

Snell's law of refraction states that;

n1 sinθ1 = n2 sinθ2

Where;

n1 is refractive index of incidence medium

θ1 is angle of incidence

n2 is Refractive index of refraction medium

θ2 is angle of refraction

For This question, n1 = 1.5 and n2 = 1.33

Thus;

1.5 sinθ1 = 1.33 sinθ2

Rearranging, we have;

sinθ1/sinθ2 = 1.33/1.5

We know from trigonometry, that sin 0 = 0 and sin 90 = 1. So, as θ approaches 0°, the value of sinθ decreases while as it approaches 90°,the value of sinθ increases.

Thus, by inspection, we can say that the value of the denominator is higher than the numerator.

Thus, θ2 is greater than θ1

So, the angle of refraction is greater than the angle of incidence

4 0
3 years ago
When you rub two balloons on your sleeve, does it have positive or negative?
igomit [66]

When you rub the balloons, it will take electrons away, which is negative. So, the balloons are negative
6 0
3 years ago
Read 2 more answers
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