Explanation:
It is given that,
Mass of person, m = 70 kg
Radius of merry go round, r = 2.9 m
The moment of inertia, 
Initial angular velocity of the platform, 
Part A,
Let 
is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :
Here, 
Solving the above equation, we get the value as :
Part B,
The initial rotational kinetic energy is given by :
The final rotational kinetic energy is given by :
Hence, this is the required solution.
Answer:
600 Joules
Explanation:
Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.
Answer:
14 m/s²
Explanation:
Start with Newton's 2nd law: Fnet=ma, with F being force, m being mass, and a being acceleration. The applied forces on the left and right side of the block are equivalent, so they cancel out and are negligible. That way, you only have to worry about the y direction. Don't forget the force that gravity has the object. It appears to me that the object is falling, so there would be an additional force from going down from weight of the object. Weight is gravity (can be rounded to 10) x mass. Substitute 4N+weight in for Fnet and 1kg in for m.
(4N + 10 x 1kg)=(1kg)a
14/1=14, so the acceleration is 14 m/s²
Answer: The displacement is 1 block.
Explanation:
Let's define:
The right is the positive side.
The left is the negative side.
Then if you start at position A, and you walk N blocks to the right, the new position is:
A + N
And if you start at position A, and you walk M blocks to the left, the new position is:
A - M.
In this case, we know that Kayla starts at -3 and she walks 5 blocks to the right.
Then her new position is:
-3 + 5 = 2
Now she walks 3 blocks to the left, then her new position is:
2 - 3 = -1
The displacement will be equal to the difference between the final position (-1) and the initial position (-2)
Then the displacement is:
D = -1 - (-2) = -1 +2 = 1
The displacement is 1 block.
