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umka2103 [35]
3 years ago
12

If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

(1,1)

Step-by-step explanation:

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NeTakaya
I think answer is 9.3 after it’s rounded
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Vedmedyk [2.9K]

Answer:

the first answer is correct

the second answer is correct if they messed up on the question and meant to ask for the MAD of set B

I think the 3rd answer is incorrect (I got 1.09), so you might want to double-check your 3rd answer since it is asking for "times bigger", not how much bigger, which means how many times larger is the MAD of set A than that of set B and to find how many times bigger a number is than another number, you have to divide the first number by the second number.

Step-by-step explanation:

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3 years ago
What would the number, 4 tens + 3 + eight hundred thousand + 5000 look like?
qwelly [4]
805043 would be the answer i believe
3 0
2 years ago
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3 amigos llevaron a cabo un negocio que genera una ganancia que genera una ganancia de 1200$ si lo que aporto cada uno para el n
lana66690 [7]
Let's define variables:
 x1: Friend 1 contribution for the business
 x2: Friend 2 contribution for the business
 x3: Friend 3 contribution for the business
 The total contribution is:
 C = x1 + x2 + x3&#10;&#10;C = 500 + 350 + 200&#10;&#10;C = 1050
 The percentage that each one contributes is given by:
 Pi = = (xi / C) * 100&#10;
 Where,
 i = 1, 2, 3
 Calculating we have:
 P1 = (x1 / C) * 100 = (500/1050) * 100 = 47.61904762&#10;&#10;P2 = (x2 / C) * 100 = (350/1050) * 100 = 33.33333333&#10;&#10;P3 = (x3 / C) * 100 = (200/1050) * 100 = 19.04761905
 Thus, the profit of each one is:
 Gi = (Pi / 100) * 1200&#10; 
Calculating we have:
 G1 = (P1 / 100) * 1200 = (47.61904762 / 100) * 1200 = 571.43 $&#10;&#10;G2 = (P2 / 100) * 1200 = (33.33333333 / 100) * 1200 = 400 $&#10;
 G3 = (P3 / 100) * 1200 = (19.04761905 / 100) * 1200 = 228.57 $
 Answer:
 To each corresponds:
 
571.43, 400, 228.57
 
Respectively
8 0
3 years ago
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