1. If the product of these integers is to be 1, then all of them must be either 1 or -1.
2. Since the product is positive (+1), it must be that there are an *even* number of negative ones (-1), if any.
3. If the sum were 0 it would mean that the number of +1's must equal the number of -1's. So that means there would have to be exactly 22/2=11 of each.
4. But if there were 11 of each, that means the number of -1's would be *odd* and there's no way the product could be +1 (as stated in 2 above).
Hence, the sum is never 0, if the product of 22 integers is equal +1.
Answer:
no solution
Step-by-step explanation:
no solution x=0
<span><span> x-4/x3-64</span> </span>Final result :<span> x4 - 64x3 - 4
—————————————
x3 </span>
Step-by-step explanation:
<em> </em><em>REFER</em><em> </em><em>TO</em><em> </em><em>THE</em><em> </em><em>ATTACHMENT</em><em> </em>
<em>HEY</em><em> </em><em>IN</em><em> </em><em>WHICH</em><em> </em><em>CLASS</em><em> </em><em>YOU</em><em> </em><em>ARE</em><em> </em><em>ROSA</em>
