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Elena-2011 [213]
3 years ago
10

Cara has 25$ to buy dry pet food and treats for the animal shelter. A pound of dog food cost $2 and treats are $1 apiece. If she

buy 9 pounds of food, what is the greatest number of treats she can buy? Write an inequality for the situation
Mathematics
1 answer:
alina1380 [7]3 years ago
5 0
Let x be the number of treats bought
Let y be the pounds of food bought

25= 2y+x

Given that she has buys 9 pounds of dog food:

25= 2(9)+x
25=18 +x
25-18 =x
7=x

With the money she has left over, she can buy 7 treats.

Hope I helped :)
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monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

and the integral of \frac1{x^2} converges over the same domain, so this integral must also converge by comparison.

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\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}

8 0
3 years ago
In the 2000-2001 season, Shaquille O'Neal made 813 field goals out of 1422 attempts. What was his ratio of successful field goal
iragen [17]
Answer=1.335 or 1 67/200

813 field goals
1422 attempts

1422-813=609 fails

813/609=1.335 successes per fail

1.335= 1 335/1000= 1 67/200
7 0
3 years ago
if joelle multiplied 792 by a positive integer and came up with a perfect square, what is the smallest integer she could have mu
antoniya [11.8K]
The positive integer is 22.
7 0
3 years ago
חן
N76 [4]

Answer:

Step-by-step explanation:

This is a fascinating question. It turns out to be true because of the relationship between a 30 degree angle and a 60 degree angle

The answer is that the product of sin30*sin60 = cos(30)*cos(60). This happens because sin(60) = cos(90-60) = cos(30)

Other angles will do the same thing sin36 * sin54 = cos(54)*cos(36)

8 0
2 years ago
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees a
Ivenika [448]

Answer:

<h2>70 possible groups</h2>

Step-by-step explanation:

Given the total number of employee to be equal to 12 temporary employee.

Number of women employee = 5 women

Number of men employee = 12 - 5 = 7 men

If 4 will be hired as permanent employees, the possible ways they can be grouped so that the 4 temporary employees consists of 3 women and 1 man can be done by applying the combination formula.

Combination has to do with selection. For example, if r objects are to be selected from n pool of similar objects, this can be done in <em>nCr </em>different ways.

nCr = \frac{n!}{(n-r)!r!}

According to question, we are to select 3 women from 5 women and 1 man from 7 men. Based on similarity in sex, this can be done in (5C3* 7C1) different ways .

5C3 * 7C1\\=  \frac{5!}{(5-3)!3!} * \frac{7!}{(7-1)!1!}\\\\= \frac{5!}{2!3!} * \frac{7!}{6!1!}\\\\=  \frac{5*4*3!}{3!*2} * \frac{7*6!}{6!*1}\\\\= \frac{20}{2} * \frac{7}{1}\\  \\= 10*7\\\\= 70\ possible\ groups

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3 years ago
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