ANSWER

EXPLANATION
The given function is;

The constant term is 11.
The coefficient of the leading term is 5.
The factors of 11 are ±1,±11
The factors of 5 are ±1,±5
According to the Rational roots Theorem,
the potential roots are obtained by expressing the factors of the constant term over the coefficient of the leading term.

We have been given the expression

We have the exponent rule

Using this rule, we have

Now, using the fact that
, we get
![x^{\frac{9}{7}}= \sqrt[7]{x^9}\\ \\ x^{\frac{9}{7}}=\sqrt[7]{x^7\times x^2}\\ \\ x^{\frac{9}{7}}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%20%5Csqrt%5B7%5D%7Bx%5E9%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%5Ctimes%20x%5E2%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D)
D is the correct option.
The final amount of yards the team has is 8 yards.
Surface of a cubical box=6(side²)
1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface ⇒surface=cost of painting/rate
Data:
Rate=$15/m²
cost of painting=$1440
Surface=$1440/($15/m²)=96 m²
2)We find out the length of the side:
Surface of a cubical box=6(side²)
Data:
Surface of a cubical box=96 m2
Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m
3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³
Answer: the volume of this cubical box would be 64 m³.