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quester [9]
3 years ago
11

Draw a parallel line to line PQ, Start the line with point R

Mathematics
2 answers:
ryzh [129]3 years ago
7 0

Answer:It’s a long triangle

^^^^^^^^^^^^^^^^^^^^^^^^^^

elena-s [515]3 years ago
4 0

Answer:Howwwwwwww!!!!!!.”?.?....?.??.??.

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Enter the values for the highlighted variables to complete the steps to find the sum:
sergey [27]

Answer:

a ⇒ -1

b ⇒ -9

c ⇒ 9

d =  3

e ⇒ 3

f ⇒ 2

g ⇒ 1.5

Step-by-step explanation:

Answers off of Edge 2020

6 0
3 years ago
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What is f(-4) if f(x)=|7x-3|
MrRissso [65]
Substitute the given into the function

f(-4) = |7(-4) - 3|
now solve
f(-4) = |-28 - 3|
f(-4) = | -31| 
the absolute value of |-31| is 31
so, 
f(-4) = 31

Hope this helps :)
8 0
3 years ago
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Is the triangle an acute, isosceles, obtuse, or right?
Trava [24]

Step-by-step explanation:

k =70 because all triangles angles add up to 180° and it's an acute angle cause all the angles are lower than 90° hope this helps

5 0
3 years ago
What is 4/5 as a percent<br><br> What is 7/8 as a percent
Gwar [14]

Answer: 4/5=80%

7/8= 87.5%

Step-by-step explanation: 4 divided by 5 is 0.8, meaning the percentage is 80%

7 divided by 8 is 0.875, meaning the percentage is 87.5

5 0
3 years ago
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A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
3 years ago
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