Answer:
2500 Square meters
Step-by-step explanation:
Given the garden area (as a function of its width) as:
The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.
A'(w)=-2w+100
-2w+100=0
-2w=-100
w=50 meters
Since Marquise has 200 meters of fencing to build a rectangular garden,
Perimeter of the proposed garden=200 meters
Perimeter=2(l+w)
2(l+50)=200
2l+100=200
2l=200-100=100
l=50 meters
The dimensions that will yield the maximum area are therefore:
Length =50 meters
Width=50 meters
Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>
1 ft = 12 inches
so 2 ft = (2 * 12) = 24 inches
and 1/4 ft = 1/4 * 12 = 12/4 = 3 inches
for a total of 27 inches
Answer:(a) BA = (-3,2) (b) BC = (-9,6)
Step-by-step explanation: (a) Vector BA = position vector of B - position vector of A = vector OB - vector OA = (3-6) i + (4-2) j = -3i+2j [i, j are unit vectors along x and y-axis respectively]. Also vector BA=(-3,2). (b) Vector BC = position vector of B - position vector of C = vector OB - vector OC = (3-12) i + (4-(-2)) j = -9i+6j [i, j are unit vectors along x and y-axis respectively]. Also vector BA=(-9,6).
Answer:
TURS is parallelogram => TS=UR <=> 2x + 15 = x + 15
=> x = 0
the answer is C
Step-by-step explanation:
