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2 years ago

14

78 ÷ 8 is equivalent to 78.00 ÷ 8. We can write zeros in the tenths place and hundredths place without changing the value. Use t

he algorithm to solve.

2 answers:

Shtirlitz [24]2 years ago

6 0

9.75 all you need to to is divide 78 by 8 which would equal 9.75

Nutka1998 [239]2 years ago

4 0

Answer:

9.75

Step-by-step explanation:

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PLZZZ HELP 3RD TIME ASKING THIS IS WORTH 40% OF MY GRADE

den301095 [7]

Answer:

112

Step-by-step explanation:

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2 years ago

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Jerry starts with $1400 in a college savings account. His account earns interest at a rate of 2.7%

tigry1 [53]

Answer: There will be $ 1687.02 in the account after 7 years.

Step-by-step explanation:

Formula to find the accumulated amount (A) in account on principal amount (P) with rate of interest (r) in 't' years is given by :-

$A=P(1+r)^t$

As per given, P = $1400

r= 2.7% = 0.027

t= 7 years

Then,

$A= 1400(1+0.027)^7\\\\= 1400(1.027)^7\\\\= 1400(1.2050168)\\\\= 1400(1.2050168)\approx1687.02$

Hence, there will be $ 1687.02 in the account after 7 years.

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2 years ago

What is the domain of (f/g)(x) if f(x)=x g(x)=1

stepan [7]

Answer:

Domain: (-∞,∞) OR All Real Numbers

Step-by-step explanation:

(f/g)(x) ⇒ f(x)/g(x) ⇒ x/1

Therefore, we look at the domain of the function x/1. There will almost always only be a gap if the denominator = 0. However, 1 ≠ 0, so therefore, there are no gaps or endpoints. Therefore, the domain is all real numbers

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3 years ago

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If k‐th term of a sequence is ak = ( -1) ^k(2-k)k/2k-1

max2010maxim [7]

Given:

kth term of a sequence is

$a_k=\dfrac{(-1)^k(2-k)k}{2k-1}$

To find:

The next term $a_{k+1}$ when k is even.

Solution:

We have,

$a_k=\dfrac{(-1)^k(2-k)k}{2k-1}$

Put k=k+1, to get the next term.

$a_{k+1}=\dfrac{(-1)^{k+1}(2-(k+1))(k+1)}{2(k+1)-1}$

If k is even, then k+1 must be odd and odd power of -1 gives -1.

$a_{k+1}=\dfrac{(-1)(2-k-1)(k+1)}{2k+2-1}$

$a_{k+1}=\dfrac{(-1)(1-k)(1+k)}{2k+1}$

$a_{k+1}=-\dfrac{1^2-k^2}{2k+1}$ $[\because (a-b)(a+b)=a^2-b^2]$

$a_{k+1}=-\dfrac{1-k^2}{2k+1}$

Therefore, the next term is $a_{k+1}=-\dfrac{1-k^2}{2k+1}$ .

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2 years ago

Q2. In a camp food was enough for 400 people for 23 days. If 60 more people joined the camp, find the number of days the food wi

victus00 [196]

Answer:

Q2)

We have food for 400 people, and it will last for 23 days.

Then we have an inverse relation, where the number of days decreases as the number of people increases, this means that we have a relationship like:

23 days = K/400 people.

Then we get:

(23 days)*(400 people) = K = 9200 days*people.

Now if we increase the number of people by 60, we get.

people = 460

Then the number of days that this will last is:

D = (9200 days*people)/460 people = 20 days.

The food will last for 20 days.

Q3) We have a proportional relationship (y = k*x) such that y = 40 when x = 200, then we get:

40 = k*200

With this, we can find the value of k

40/200 = k = 0.2

Then the proportional relationship is:

y = 0.2*x

a) We need to replace x by 15.

y = 0.2*15 = 3

y = 3

b) We need to replace y by 8.

8 = 0.2*x

8/0.2 = x = 40

x = 40

Q3) y is inversely proportional to x (y = k/x), and y = 8 when x = 30.

Then we get:

8 = k/30

Then the value of k is:

8*30 = k = 240

then the relationship is:

y = 240/x

a) we need to replace x by 4

y = 240/4 = 60

y = 60

b) we need to replace y by 360

360 = 240/x

360*x = 240

x = 240/360 = 0.666...

x = 0.666...

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2 years ago