Which pair of concurrent forces could produce a resultant force having a magnitude of 10. Newtons?

Question 24(Multiple Choice Worth 2 points)

vladimir2022 [97]

Question 24.
The Environmental Protection Agency is a regulatory agency that protects human and environmental life. Because it is a regulatory agency, it oversees all actions that has a direct effect on the environment. Letter A could be an answer, but not the best. The EPA does not trust environmentalists because they still have to inspect the ship. Maybe the ship would drive away fishes from their aquatic homes which would cause an imbalance in the ecosystem. So, the best answer would be letter C.

Question 25:
Gravity is a force of attraction that acts as the pull towards the object's center. According to Newton's Law of Universal Gravitation, the force of gravity is directly proportional to the mass, and inversely proportional to distance. The heavier and nearer the objects are, the greater the force of gravity. Every object in the world is acted upon by gravity, whether at rest or moving. Therefore, the answer is <span>B.

Question 26:
Power is the amount of work done per unit time. So, if time is not changed and work increases, the power will have to increase as well. The answer is C.

Question 27:
In electricity, the power of the load in a circuit is equal to the product of its voltage and current. Therefore, voltage and current are directly proportional to power. But they are inversely proportional to each other. So, if voltage increases, the power also increases. Therefore, the answer is B.

Question 28:
Hybrid cars work on the energy both coming from oil and electricity. Electricity is a more expensive fuel than oil. So, you will expect that hybrid cars are much more expensive. Electricity comes from batteries, which is made up of electrolyte solutions of metals. They are non-renewable source as well. The only advantage is that, batteries do not emit pollutant gases unlike oil. These gases deteriorate the ozone layer which protects the Earth from exposure to UV rays. Therefore, the answer is B.</span>

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3 years ago

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PA HELP PO NEED KO ANSWER AS FAST AS POSSIBLE <br>I will mark you as brainliest

uysha [10]

Answer:

is there paragraph or not ?

Explanation:

https://glaquarium.org/wp-content/uploads/2015/06/Final-Becoming-a-Scientist-Observation-and-Questions-Lesson-Plan.pdf

6 0

3 years ago

Find the linear function C Equals=f(F) that gives the reading on the Celsius temperature scale corresponding to a reading on th

Juli2301 [7.4K]

Answer:

a. C(F) = (5/9).F - (160/9)

b. They both readings are equal at C = F = - 40

Explanation:

They are telling us that we are looking for a linear function

If C(F) = a.F + b is the linear function, we use the data to find a and b

C(32) = a.32 + b

0 = a.32 + b

b = - (a.32) (1)

And then

C(212) = a.212 + b

100 = a.212 + b (2)

replacing (1) in (2) we obtain

100 = a.212 + [-(a.32)]

100 = a.212 - a.32

100 = 180.a

a = 100/180

a = 5/9

If a = 5/9 then b = -(a.32)

b = - (5/9).32

b = - (160/9) and the linear function is

C(F) = (5/9).F - (160/9)

For b. they are asking us for a X reading. We must equalize C and F

X = (5/9).X - (160/9)

(4/9).X = - (160/9)

X = -40

C = F at temperature X = - 40

6 0

3 years ago

Which statement is true about alkali metals? A. Some of them explode when exposed to water. B. They are in group 18 of the perio

WINSTONCH [101]

The Answer To This Is A , The Most Reactive Of The Alkali Explode Due To Reactions To Water

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Can someone solve this problem and explain to me how you got it

Zarrin [17]

1) The electric force changes by a factor of 25

2) The electric force changes by a factor of 16/9

Explanation:

1)

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, let's call F the initial force between the two charges when they are at a distance of r.

Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is

r' = 5r

Therefore, the new force between the charges is:

$F' = k' \frac{q_1 q_2}{r'^2}=k' \frac{q_1 q_2}{(5r)^2}=\frac{1}{25}(k' \frac{q_1 q_2}{r'^2})=\frac{F}{25}$

So, the force has changed by a factor of 25.

2)

The original force between the two charges is

$F=k\frac{q_1 q_2}{r^2}$

In this problem, we have:

- The distance between the charges is changed by a factor of 6:

r' = 6r

- The charges are both changed by a factor of 8:

$q_1' = 8q_1$

$q_2' = 8q_2$

Substituting into the equation, we find the new force:

$F' = k' \frac{q_1' q_2'}{r'^2}=k' \frac{(8q_1) (8q_2)}{(6r)^2}=\frac{64}{36}(k' \frac{q_1 q_2}{r'^2})=\frac{16}{9}F$

So, the force has changed by a factor of 16/9.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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3 years ago