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3 years ago

Which terms in the following expression are like terms?

Mathematics

1 answer:

Alinara [238K]3 years ago

6 0

9514 1404 393

Answer:

Step-by-step explanation:

Like terms have the same variable(s) to the same power(s).

The terms of this expression are ...

x^3: variable x, power 3
5x: variable x, power 1
-3x: variable x, power 1
3y: variable y, power 1
4: no variable
-1: no variable

The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.

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What is 3/5 of 7 kg ?

MAVERICK [17]

What is 3/5 of 7 kg ?

of = multiplication

3/5 × 7 = ?
0.6 × 7 =
4.2

3/5 of 7 kg is 4.2 kg.

3 0

4 years ago

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Solve each equation r - 5 1/6 = 10 please help me Thank youuu!

Charra [1.4K]

[tex}r - 5 \frac{5}6 + 5\frac{5}6 = 10 +5\frac{5}6{/tex] $r=15 \frac{5}6$

5 0

3 years ago

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1.Encuentra de dos formas diferentes el área de las figuras mostradas en cada literal:

MA_775_DIABLO [31]

Answer:

Cuadrilátero A: $A = y^{2}+4\cdot y +4$

Cuadrilátero B: $A = a^{2}+6\cdot a + 9$

Step-by-step explanation:

Existen dos formas distintas de determinar las áreas de cada cuadrilátero:

(i) Obtener el área de cada cuadrado y sumar los resultados.

(ii) Calcular los lados del cuadrilátero grande y determinar el área.

Cuadrilátero A

Método (i)

$A = y^{2}+2\cdot y +4+2\cdot y$

$A = y^{2}+4\cdot y +4$

Método (ii)

$A = (y+2)\cdot (y+2)$

$A = y^{2}+4\cdot y + 4$

Cuadrilátero B

Método (i)

$A = a^{2}+3\cdot a +9 + 3\cdot a$

$A = a^{2}+6\cdot a +9$

Método (ii)

$A = (a+3)\cdot (a+3)$

$A = a^{2}+6\cdot a + 9$

8 0

3 years ago

The diagonal of a square is 8 cm.

VladimirAG [237]

the length of the side of this square is $4\sqrt{2} \:or \:5.65$ cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²= $\frac{64}{2}$

a²=32

doing square root on both side

$\sqrt{a²}=\sqrt{32}$

a=± $\sqrt{2*2*2*2*2}$

a=±2*2 $\sqrt{2}$

Since side of square is always positive so

a=4 $\sqrt{2}$ or 5.65 cm

6 0

3 years ago

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17. When a single set of values is randomly divided into two equal groups, explain how the means of these two groups may be very

joja [24]

If you take 2 groups of equal cardinality, it could happen that, for example, many of the higher values go to the first group and therefore, many of the low values go to the second group, making their respective means quite different and different from the original sample mean. This could even go worse due to the possible existence of outliers, that is, values that are far different than the sample mean. An outlier tend to disrup the mean of a sample, but for smaller samples the result is much dramatic.

For example, let X be {1,2,3,4,5,6,7,8,9,100}

The elements of X sum 145, hence the mean of X is 14,5. Let divide X in two groups

Y = {1,2,3,5,9}

Z = {4,6,7,8,100}

The elements of Y sum 20, so its mean is 4

The elements of Z sum 125, so its mean is 25

Both means are quite different from each other and quite different from the mean of X. Note that if we take the mean of the means the result is 4+25/2 = 14,5 which is equal to the mean of X.

7 0

3 years ago