Answer:
To find the hypotenuse you need to use the Pythagorean Theorem which is
a^2+b^2=c^2
Where a and b are your two sides and c is your diagonal line
So you want to plug the numbers in for the right variables
5^2+12^2=c^2
We want to find what c equals so we are first gonna simplify
25+144=c^2
we take 5^2=25, and 12^2=144, then we add them together 25+144=169
169=c^2 now you want to take 169 and square root it because the opposite of squaring is taking it by the root square
The square root of 169=13
Your hypotenuse is 13
Hope this helps ;)
Answer:
43
Step-by-step explanation:
Let
The unit digit = x
The tens digit = y
The number = 10x + y
The tens digit of a two-digit number is five more than the units digit.
y = x + 5
Seven times the sum of the digits of this number is 3 less than the number itself.
7(x + y) = 10x + y - 3
7x + 7y = 10x + y - 3
Find the number.
We substitute x + 5 for y
7x + 7(x + 5) = 10x + (x + 5) - 3
7x + 7x + 35 = 10x + x + 5x - 3
14x + 35 = 11x + 5x - 3
Collect like terms
35 + 3 = 11x + 5x -14x
38 = 16x - 14x
38 = 2x
x = 38/2
x = 19
Solving for y
y = x + 5
y = 19 + 5
y = 24
The number = 19 + 24
= 43
Answer:
d. 944 mm^3
Step-by-step explanation:
The area of a circle is given by ...
A = πr² . . . . . where r is the radius, half the diameter
The area of a circle with diameter 9 mm is ...
A = π(4.5 mm)² = 20.25π mm²
The area of the semi-circular end of the prism is half this value, or ...
semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²
__
The area of the rectangular portion of the end of the prism is the product of its width and height:
A = wh = (9 mm)(6 mm) = 54 mm²
Then the base area of the prism is ...
base area = rectangle area + semicircle area
= (54 mm²) +(31.809 mm²) = 85.809 mm²
__
This base area multiplied by the 11 mm length of the prism gives its volume:
V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³
The volume of the composite figure is about 944 mm³.
So 1 would be 5r+20 and then the second one would be
We have that
<span>the equation
y=-3x</span>²<span> + x -4
the </span><span>real number solutions are the points x intercept of the graph
are the points when y=0
using a graph tool
see the attached figure
</span><span>the graph has no point of intersection with the x axis
</span>therefore
the answer is
there are zero real numbers solutions
